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Determine the forces exerted at C and E on the tong BCE.

Determine the forces exerted at C and E on the tong BCE.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Problem 6.141** A steel ingot weighing 8000 lb is lifted by a pair of tongs as shown. Determine the forces exerted at C and E on the tong BCE. --- This exercise involves analyzing the forces acting on a mechanical lifting device. A pair of tongs is used to lift a steel ingot weighing 8000 pounds. The objective is to calculate the specific forces exerted at specific points, labeled C and E, on the tong BCE. This type of problem typically involves understanding concepts of static equilibrium, force decomposition, and moments. **Understanding the Problem:** - **Weight of Ingot:** 8000 lb - **Points of Interest:** C and E on the tong BCE **Approach:** 1. **Free Body Diagram (FBD):** - Draw an FBD representing the tong as a rigid body. - Identify all acting forces, including the weight of the ingot and reaction forces at the points C and E. 2. **Equilibrium Equations:** - Apply the conditions for static equilibrium: sum of forces in all directions should equal zero, and the sum of moments about any point should also equal zero. - Use these equations to solve for the unknown forces at C and E. **Applications:** This problem is practical for understanding real-world applications like material handling in manufacturing, construction, or logistics, where understanding the proper application of forces ensures safety and efficacy in operations.
Transcribed Image Text:**Problem 6.141** A steel ingot weighing 8000 lb is lifted by a pair of tongs as shown. Determine the forces exerted at C and E on the tong BCE. --- This exercise involves analyzing the forces acting on a mechanical lifting device. A pair of tongs is used to lift a steel ingot weighing 8000 pounds. The objective is to calculate the specific forces exerted at specific points, labeled C and E, on the tong BCE. This type of problem typically involves understanding concepts of static equilibrium, force decomposition, and moments. **Understanding the Problem:** - **Weight of Ingot:** 8000 lb - **Points of Interest:** C and E on the tong BCE **Approach:** 1. **Free Body Diagram (FBD):** - Draw an FBD representing the tong as a rigid body. - Identify all acting forces, including the weight of the ingot and reaction forces at the points C and E. 2. **Equilibrium Equations:** - Apply the conditions for static equilibrium: sum of forces in all directions should equal zero, and the sum of moments about any point should also equal zero. - Use these equations to solve for the unknown forces at C and E. **Applications:** This problem is practical for understanding real-world applications like material handling in manufacturing, construction, or logistics, where understanding the proper application of forces ensures safety and efficacy in operations.
The diagram illustrates a mechanical lifting system supporting an 8000 lb weight, suspended by a series of bars and joints. - The system consists of a pair of crossed links: \( A \) to \( C \) and \( B \) to \( D \), with arrows at the top indicating points \( A \) and \( B \) with upward forces. - The distance between points \( A \) and \( B \) is 14 inches. - The horizontal span from point \( C \) to \( D \) is 45 inches. - Vertical distances are indicated: from \( A \) to \( C \) and \( B \) to \( D \) is 35 inches, and from \( C \) (or \( D \)) to the base points \( E \) and \( F \) is 55 inches. - The weight is directly attached at the bottom between points \( E \) and \( F \), which are 55 inches apart horizontally. - The complete assembly shows a mechanical structure that likely operates in a symmetrical manner to balance and lift the central load. This diagram (Fig. P6.141) aids in understanding the geometric and force relationships within the lift mechanism.
Transcribed Image Text:The diagram illustrates a mechanical lifting system supporting an 8000 lb weight, suspended by a series of bars and joints. - The system consists of a pair of crossed links: \( A \) to \( C \) and \( B \) to \( D \), with arrows at the top indicating points \( A \) and \( B \) with upward forces. - The distance between points \( A \) and \( B \) is 14 inches. - The horizontal span from point \( C \) to \( D \) is 45 inches. - Vertical distances are indicated: from \( A \) to \( C \) and \( B \) to \( D \) is 35 inches, and from \( C \) (or \( D \)) to the base points \( E \) and \( F \) is 55 inches. - The weight is directly attached at the bottom between points \( E \) and \( F \), which are 55 inches apart horizontally. - The complete assembly shows a mechanical structure that likely operates in a symmetrical manner to balance and lift the central load. This diagram (Fig. P6.141) aids in understanding the geometric and force relationships within the lift mechanism.
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6.142 If the toggle shown is added to the tongs of Prob. 6.141 and the load is lifted by applying a single force at G, determine the forces exerted at C and E on the tong BCE.
Transcribed Image Text:6.142 If the toggle shown is added to the tongs of Prob. 6.141 and the load is lifted by applying a single force at G, determine the forces exerted at C and E on the tong BCE.
A 8000 lb G -73 in.- Fig. P6.142 B 20 in.
Transcribed Image Text:A 8000 lb G -73 in.- Fig. P6.142 B 20 in.
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