Determine the force in menmbers CH and CF. -2 m -2 m 2 m -2 m E |A B 2 m (F 24 kN

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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**Title: Truss Analysis: Determining Forces in Members CH and CF**

**Objective:**

To determine the forces in members CH and CF of the truss structure shown, using static equilibrium equations.

**Diagram Explanation:**

- The diagram illustrates a truss structure with joints labeled A, B, C, D, E, F, G, H, and I.
- The horizontal distances between each joint (A-B, B-C, C-D, D-E) are each 2 meters, making the total length 8 meters.
- The vertical distance from joint A to the support I is 2 meters.
- External forces of 24 kN are applied vertically downward at joints E, F, and G.
- The structure is supported at A and I, with I indicating a pin support, which allows rotation but not translation.
- Members of interest: CH and CF.

**Approach:**

1. **Static Equilibrium Equations**:
   - Ensure the sum of all forces in the horizontal and vertical directions is zero.
   - Ensure the sum of moments about any point is zero.

2. **Joint Method**:
   - Analyze each joint starting from a joint with known forces or supports.
   - Use equations of equilibrium to solve for unknown forces in each member.

3. **Member Forces**:
   - Identify forces in members based on equilibrium conditions from adjacent joints.
   - Determine whether the force is tensile or compressive.

This setup is a practical example for students learning structural analysis, emphasizing methodical problem-solving in engineering statics.
Transcribed Image Text:**Title: Truss Analysis: Determining Forces in Members CH and CF** **Objective:** To determine the forces in members CH and CF of the truss structure shown, using static equilibrium equations. **Diagram Explanation:** - The diagram illustrates a truss structure with joints labeled A, B, C, D, E, F, G, H, and I. - The horizontal distances between each joint (A-B, B-C, C-D, D-E) are each 2 meters, making the total length 8 meters. - The vertical distance from joint A to the support I is 2 meters. - External forces of 24 kN are applied vertically downward at joints E, F, and G. - The structure is supported at A and I, with I indicating a pin support, which allows rotation but not translation. - Members of interest: CH and CF. **Approach:** 1. **Static Equilibrium Equations**: - Ensure the sum of all forces in the horizontal and vertical directions is zero. - Ensure the sum of moments about any point is zero. 2. **Joint Method**: - Analyze each joint starting from a joint with known forces or supports. - Use equations of equilibrium to solve for unknown forces in each member. 3. **Member Forces**: - Identify forces in members based on equilibrium conditions from adjacent joints. - Determine whether the force is tensile or compressive. This setup is a practical example for students learning structural analysis, emphasizing methodical problem-solving in engineering statics.
Expert Solution
Step 1

Pass the section directly through member CD, CF, and FG and analyze the portion of the truss to the right, because there are no supports or unknown reaction forces on the right section.

Mechanical Engineering homework question answer, step 1, image 1

Assume all members are in tension.

Mechanical Engineering homework question answer, step 1, image 2

 

Step 2

Determine the moment about point E and equate it to zero.

Mechanical Engineering homework question answer, step 2, image 1

 

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