**Problem Statement:**Determine the force in member \( BE \) of the loaded truss. The force is positive if in tension, negative if in compression.**Diagram Explanation:**The diagram depicts a truss with several members and applied forces:- The truss has a vertical alignment on the left side with points \(\text{A, B, C, D}\) and a diagonal member connecting to \(E\).- Horizontal member \( \text{EF} \) connects \(E\) to a roller at \(G\).- Applied forces are as follows: - \(5 \, \text{kN}\) force to the left at point \(D\) - \(7 \, \text{kN}\) force to the left at point \(C\) - \(5 \, \text{kN}\) force to the left at point \(B\)- Each segment \( \text{AB, BC, CD} \) is \(5 \, \text{m}\) in length.- The horizontal distance between points \( A \) and \( G \) is \(6 \, \text{m}\).**Calculation Box:**- Answer space for the force in member \( BE \): \[ \text{Answer: } BE = \quad \text{kN} \]

Given data:-determining the angle θ*from △ADGAD=15m,AG=6mtanθ=615θ=tan-1615=21.80°*length of…

Answered: Determine the force in member BE of the…

Determine the force in member BE of the loaded truss. The force is positive if in tension, negative if in compression. 5 kN 5 m 7 kN E 5 m B 5 kN 5 m A.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

**Problem Statement:**

Determine the force in member \( BE \) of the loaded truss. The force is positive if in tension, negative if in compression.

**Diagram Explanation:**

The diagram depicts a truss with several members and applied forces:

- The truss has a vertical alignment on the left side with points \(\text{A, B, C, D}\) and a diagonal member connecting to \(E\).
- Horizontal member \( \text{EF} \) connects \(E\) to a roller at \(G\).
- Applied forces are as follows:
- \(5 \, \text{kN}\) force to the left at point \(D\)
- \(7 \, \text{kN}\) force to the left at point \(C\)
- \(5 \, \text{kN}\) force to the left at point \(B\)
- Each segment \( \text{AB, BC, CD} \) is \(5 \, \text{m}\) in length.
- The horizontal distance between points \( A \) and \( G \) is \(6 \, \text{m}\).

**Calculation Box:**

- Answer space for the force in member \( BE \):
\[
\text{Answer: } BE = \quad \text{kN}
\]

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