Determine the force between two charges that are 200 m apart, if the first charge is +0.25 C and the second charge is +4.0 C?

College Physics
11th Edition
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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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14. Determine the force between two charges that are 200 m apart, if the first charge is +0.25 C and the second charge is +4.0 C?

Formulas:
F = ma
weight = mg
Xp = X; + V;t + at?
Vf = Vị + at
W = Fd
PEG = mgh
mv?
%D
KE =
Fs = -kx
PEĘ = -kx2
%3D
small force X BIG DISTANCE = BIG FORCE X small distance
P = =
F1
F2
FB = PriuiaVg
%3D
%3D
A1
A2
P, + -pv? + pgh,
= P2 + pv3 + pgh,
Q = MCAT = mc(T, – T,)
v = af T= 2m =
T = 2n
k
%3D
F = k Q1Q2
r2
%3D
Constant: g = 9.8 m/s?
Sea Level Air Pressure = 101 kPa
P(water)
= 1000 kg
k = 8.988 × 109 Nm2
C2
Transcribed Image Text:Formulas: F = ma weight = mg Xp = X; + V;t + at? Vf = Vị + at W = Fd PEG = mgh mv? %D KE = Fs = -kx PEĘ = -kx2 %3D small force X BIG DISTANCE = BIG FORCE X small distance P = = F1 F2 FB = PriuiaVg %3D %3D A1 A2 P, + -pv? + pgh, = P2 + pv3 + pgh, Q = MCAT = mc(T, – T,) v = af T= 2m = T = 2n k %3D F = k Q1Q2 r2 %3D Constant: g = 9.8 m/s? Sea Level Air Pressure = 101 kPa P(water) = 1000 kg k = 8.988 × 109 Nm2 C2
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