Determine the equation of the tangent plane and a vector equation of the normal line to x²y4ze+y +35=0 at (3,-3,2). A. tangent plane: -26x + y - 4z +89 = 0, normal line: (3+26t, -3-t, 2+4t) B. tangent plane: -26x + y - 4z +89 = 0, normal line: (3-26t, -3+t, 2-4t) C. tangent plane: 26x + y - 4z+89 = 0, normal line: (3+26t, -3-t, 2+4t) D. tangent plane: 26x + y - 4z+89 = 0, normal line: (3-26t, -3+t, 2-4t)
Determine the equation of the tangent plane and a vector equation of the normal line to x²y4ze+y +35=0 at (3,-3,2). A. tangent plane: -26x + y - 4z +89 = 0, normal line: (3+26t, -3-t, 2+4t) B. tangent plane: -26x + y - 4z +89 = 0, normal line: (3-26t, -3+t, 2-4t) C. tangent plane: 26x + y - 4z+89 = 0, normal line: (3+26t, -3-t, 2+4t) D. tangent plane: 26x + y - 4z+89 = 0, normal line: (3-26t, -3+t, 2-4t)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Determine the equation of the tangent plane and a vector equation of the normal line to
x²y - 4ze+y +35= 0 at (3,-3,2).
A. tangent plane: -26x + y −4z +89 = 0, normal line: (3+26t, -3-t, 2+4t)
B. tangent plane: -26x + y - 4z +89 = 0, normal line: (3-26t, -3+t, 2-4t)
C. tangent plane: 26x + y − 4z +89 = 0, normal line: (3+26t, -3-t, 2+4t)
D. tangent plane: 26x + y - 4z +89 = 0, normal line: (3-26t, -3+t, 2-4t)
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