Determine the equation of the tangent plane and a vector equation of the normal line to x²y4ze+y +35=0 at (3,-3,2). A. tangent plane: -26x + y - 4z +89 = 0, normal line: (3+26t, -3-t, 2+4t) B. tangent plane: -26x + y - 4z +89 = 0, normal line: (3-26t, -3+t, 2-4t) C. tangent plane: 26x + y - 4z+89 = 0, normal line: (3+26t, -3-t, 2+4t) D. tangent plane: 26x + y - 4z+89 = 0, normal line: (3-26t, -3+t, 2-4t)

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