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Determine the equation of the tangent plane and a vector equation of the normal line to A. tangent plane: C. tangent plane: 3 D. tangent plane: 3 4+2y-32- 3 3 3 3 B. tangent plane: +34 −3:- 3 = 0, normal line: (1–³t, 2+t, −1 – 3t In ¹ (2) = 2²(x - 2y) + 3z +3 at (4,2,-1). 3 3 4 3 -32-30, normal line: (4+2t, 2-1, −1+3t) 3 1 line: (4-t, 2+2t, -1-3t) 3 +y + y − 32 - 3 = 0, normal 3 x+2y-32-3= 0, normal line: (4+²³1, 2 - 23/t₁ −1+31) 3t

Determine the equation of the tangent plane and a vector equation of the normal line to A. tangent plane: C. tangent plane: 3 D. tangent plane: 3 4+2y-32- 3 3 3 3 B. tangent plane: +34 −3:- 3 = 0, normal line: (1–³t, 2+t, −1 – 3t In ¹ (2) = 2²(x - 2y) + 3z +3 at (4,2,-1). 3 3 4 3 -32-30, normal line: (4+2t, 2-1, −1+3t) 3 1 line: (4-t, 2+2t, -1-3t) 3 +y + y − 32 - 3 = 0, normal 3 x+2y-32-3= 0, normal line: (4+²³1, 2 - 23/t₁ −1+31) 3t

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Determine the equation of the tangent plane and a vector equation of the normal line to A. tangent plane: C. tangent plane: 3 D. tangent plane: 3 4+2y-32- 3 3 3 3 B. tangent plane: +34 −3:- 3 = 0, normal line: (1–³t, 2+t, −1 – 3t In ¹ (2) = 2²(x - 2y) + 3z +3 at (4,2,-1). 3 3 4 3 -32-30, normal line: (4+2t, 2-1, −1+3t) 3 1 line: (4-t, 2+2t, -1-3t) 3 +y + y − 32 - 3 = 0, normal 3 x+2y-32-3= 0, normal line: (4+²³1, 2 - 23/t₁ −1+31) 3t
Transcribed Image Text:Determine the equation of the tangent plane and a vector equation of the normal line to A. tangent plane: C. tangent plane: 3 D. tangent plane: 3 4+2y-32- 3 3 3 3 B. tangent plane: +34 −3:- 3 = 0, normal line: (1–³t, 2+t, −1 – 3t In ¹ (2) = 2²(x - 2y) + 3z +3 at (4,2,-1). 3 3 4 3 -32-30, normal line: (4+2t, 2-1, −1+3t) 3 1 line: (4-t, 2+2t, -1-3t) 3 +y + y − 32 - 3 = 0, normal 3 x+2y-32-3= 0, normal line: (4+²³1, 2 - 23/t₁ −1+31) 3t
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