Determine the enthalpy change, AH°, for the following reaction; N2(g) + 2H2(g) → N2H4() Given the following thermochemical equations. N2H4() + O2(g)2H20(1) + N2(g) H2(g) + ½ O2(g) → H20(/) AH° = - 622.0 kJ AH° = – 285.9 kJ +50.2 kJ -236.2 kJ +106.1 kJ 0 kJ -151.7 kJ

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Determine the enthalpy change, AH°, for the following reaction%3B
N2(g) + 2H2(g) N2H4()
Given the following thermochemical equations.
2H2O(1) + N2(g)
N2H4() + O2(g) →
H2(g) + ½ O2(g) → H20()
ΔΗ?
AH° = -285.9 kJ
->
AH° = - 622.0 kJ
%3D
+50.2 kJ
-236.2 kJ
+106.1kJ
0 kJ
-151.7 kJ
OO OOO
Transcribed Image Text:Determine the enthalpy change, AH°, for the following reaction%3B N2(g) + 2H2(g) N2H4() Given the following thermochemical equations. 2H2O(1) + N2(g) N2H4() + O2(g) → H2(g) + ½ O2(g) → H20() ΔΗ? AH° = -285.9 kJ -> AH° = - 622.0 kJ %3D +50.2 kJ -236.2 kJ +106.1kJ 0 kJ -151.7 kJ OO OOO
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