Determine the energy of a photon with a wavelength of 347 nm. (h = 6.626 x 10¯34 J•s and c = 3.00 × 10® m/s) J 1 3 4 C 7 8 +/- х 100 LO

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Educational Transcription:**

**Problem Statement:**
Determine the energy of a photon with a wavelength of 347 nm. 
(Planck's constant, \( h = 6.626 \times 10^{-34} \, \text{J} \cdot \text{s} \) and speed of light, \( c = 3.00 \times 10^8 \, \text{m/s} \))

**Calculation Interface:**
- A calculator interface with the following buttons:
  - Numbers: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9
  - Decimal point: .
  - Sign change: +/-
  - Clear: C
  - Exponentiation: x 10^□
  - Backspace: ⇦

This interface allows you to input numbers and perform calculations related to the problem statement above. 

**Explanation:**
To calculate the energy \( E \) of a photon, use the formula:
\[
E = \frac{h \cdot c}{\lambda}
\]

Where:
- \( E \) is the energy of the photon in joules (J),
- \( h \) is Planck’s constant (\( 6.626 \times 10^{-34} \, \text{J} \cdot \text{s} \)),
- \( c \) is the speed of light (\( 3.00 \times 10^8 \, \text{m/s} \)),
- \( \lambda \) is the wavelength of the photon in meters (convert 347 nm to meters by dividing by \( 10^9 \)).

**Note:**
Ensure proper unit conversion and calculation accuracy using the calculator functionality provided on the right side.
Transcribed Image Text:**Educational Transcription:** **Problem Statement:** Determine the energy of a photon with a wavelength of 347 nm. (Planck's constant, \( h = 6.626 \times 10^{-34} \, \text{J} \cdot \text{s} \) and speed of light, \( c = 3.00 \times 10^8 \, \text{m/s} \)) **Calculation Interface:** - A calculator interface with the following buttons: - Numbers: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 - Decimal point: . - Sign change: +/- - Clear: C - Exponentiation: x 10^□ - Backspace: ⇦ This interface allows you to input numbers and perform calculations related to the problem statement above. **Explanation:** To calculate the energy \( E \) of a photon, use the formula: \[ E = \frac{h \cdot c}{\lambda} \] Where: - \( E \) is the energy of the photon in joules (J), - \( h \) is Planck’s constant (\( 6.626 \times 10^{-34} \, \text{J} \cdot \text{s} \)), - \( c \) is the speed of light (\( 3.00 \times 10^8 \, \text{m/s} \)), - \( \lambda \) is the wavelength of the photon in meters (convert 347 nm to meters by dividing by \( 10^9 \)). **Note:** Ensure proper unit conversion and calculation accuracy using the calculator functionality provided on the right side.
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