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Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of an = 4.83 Å. (y T' The lattice constant of o face centered-cubicstructure is 4 75 Å Caloulate the surfac

Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of an = 4.83 Å. (y T' The lattice constant of o face centered-cubicstructure is 4 75 Å Caloulate the surfac

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HW(2 questions) Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of ao = 4.83 Å. (y TE "s The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface density of atoms for (a)a (100) plane and (b) a (110) plane. (Ans. (a) 8.86 x 104 cm-2, (b) 6.27 x 1014 cm-2]
Transcribed Image Text:HW(2 questions) Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of ao = 4.83 Å. (y TE "s The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface density of atoms for (a)a (100) plane and (b) a (110) plane. (Ans. (a) 8.86 x 104 cm-2, (b) 6.27 x 1014 cm-2]
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