Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of an = 4.83 Å. (y T' The lattice constant of o face centered-cubicstructure is 4 75 Å Caloulate the surfac
Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of an = 4.83 Å. (y T' The lattice constant of o face centered-cubicstructure is 4 75 Å Caloulate the surfac
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![HW(2 questions)
Determine the distance between nearest (110) planes in a simple cubic lattice with a
lattice constant of ao = 4.83 Å. (y TE "s
The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface
density of atoms for (a)a (100) plane and (b) a (110) plane.
(Ans. (a) 8.86 x 104 cm-2, (b) 6.27 x 1014 cm-2]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F77b38836-d96d-4166-8c3d-e4721810d582%2F9d1b0c83-d383-42ac-9139-73751da80d9e%2Fnijwdt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:HW(2 questions)
Determine the distance between nearest (110) planes in a simple cubic lattice with a
lattice constant of ao = 4.83 Å. (y TE "s
The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface
density of atoms for (a)a (100) plane and (b) a (110) plane.
(Ans. (a) 8.86 x 104 cm-2, (b) 6.27 x 1014 cm-2]
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