Determine the deflection in inches of a .75" diameter steel shaft 13" long subject to an axial force of 1600-N (E = 205-GPa) A/

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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**Exercise: Calculating Deflection in a Steel Shaft under Axial Load**

**Objective:** 
Determine the deflection in inches of a 0.75" diameter steel shaft that is 13" long, subject to an axial force of 1600 N. The modulus of elasticity (E) for the steel is given as 205 GPa.

**Details:**

- **Shaft Diameter (d):** 0.75 inches
- **Shaft Length (L):** 13 inches
- **Axial Force (P):** 1600 N
- **Modulus of Elasticity (E):** 205 GPa (Gigapascals)

**Procedure:**

- To find the deflection (Δ) of the steel shaft, we will use the formula for axial deformation:
  \[
  \Delta = \frac{{P \cdot L}}{{A \cdot E}}
  \]

  Where:
  - \( P \) is the axial force.
  - \( L \) is the length of the shaft.
  - \( A \) is the cross-sectional area of the shaft.
  - \( E \) is the modulus of elasticity.

- First, we need to convert all measurements to consistent units (preferably calculating the area in square meters if the force is in Newtons and modulus of elasticity in Pascals).

- Calculate the cross-sectional area (A) of the shaft:
  \[
  A = \pi \left( \frac{d}{2} \right)^2
  \]
  Convert d to meters first if required for consistent units with E in Pascals.

Box for calculations:
\[ \Delta = \frac{PL}{AE} \]

By following the outlined steps, the user should be able to accurately determine the deflection of the shaft in response to the given force.

(Note: The figure box for calculation is meant for students to input their answers or for an image showing the calculation steps if this is part of an online educational tool).

---

No diagrams or graphs are present in the provided image which would require additional explanation. This transcription can be used as a part of an educational exercise on calculating deflection in materials under load.
Transcribed Image Text:**Exercise: Calculating Deflection in a Steel Shaft under Axial Load** **Objective:** Determine the deflection in inches of a 0.75" diameter steel shaft that is 13" long, subject to an axial force of 1600 N. The modulus of elasticity (E) for the steel is given as 205 GPa. **Details:** - **Shaft Diameter (d):** 0.75 inches - **Shaft Length (L):** 13 inches - **Axial Force (P):** 1600 N - **Modulus of Elasticity (E):** 205 GPa (Gigapascals) **Procedure:** - To find the deflection (Δ) of the steel shaft, we will use the formula for axial deformation: \[ \Delta = \frac{{P \cdot L}}{{A \cdot E}} \] Where: - \( P \) is the axial force. - \( L \) is the length of the shaft. - \( A \) is the cross-sectional area of the shaft. - \( E \) is the modulus of elasticity. - First, we need to convert all measurements to consistent units (preferably calculating the area in square meters if the force is in Newtons and modulus of elasticity in Pascals). - Calculate the cross-sectional area (A) of the shaft: \[ A = \pi \left( \frac{d}{2} \right)^2 \] Convert d to meters first if required for consistent units with E in Pascals. Box for calculations: \[ \Delta = \frac{PL}{AE} \] By following the outlined steps, the user should be able to accurately determine the deflection of the shaft in response to the given force. (Note: The figure box for calculation is meant for students to input their answers or for an image showing the calculation steps if this is part of an online educational tool). --- No diagrams or graphs are present in the provided image which would require additional explanation. This transcription can be used as a part of an educational exercise on calculating deflection in materials under load.
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