please help **Exercise: Calculating Deflection in a Steel Shaft under Axial Load****Objective:** Determine the deflection in inches of a 0.75" diameter steel shaft that is 13" long, subject to an axial force of 1600 N. The modulus of elasticity (E) for the steel is given as 205 GPa.**Details:**- **Shaft Diameter (d):** 0.75 inches- **Shaft Length (L):** 13 inches- **Axial Force (P):** 1600 N- **Modulus of Elasticity (E):** 205 GPa (Gigapascals)**Procedure:**- To find the deflection (Δ) of the steel shaft, we will use the formula for axial deformation: \[ \Delta = \frac{{P \cdot L}}{{A \cdot E}} \] Where: - \( P \) is the axial force. - \( L \) is the length of the shaft. - \( A \) is the cross-sectional area of the shaft. - \( E \) is the modulus of elasticity.- First, we need to convert all measurements to consistent units (preferably calculating the area in square meters if the force is in Newtons and modulus of elasticity in Pascals).- Calculate the cross-sectional area (A) of the shaft: \[ A = \pi \left( \frac{d}{2} \right)^2 \] Convert d to meters first if required for consistent units with E in Pascals.Box for calculations:\[ \Delta = \frac{PL}{AE} \]By following the outlined steps, the user should be able to accurately determine the deflection of the shaft in response to the given force.(Note: The figure box for calculation is meant for students to input their answers or for an image showing the calculation steps if this is part of an online educational tool).---No diagrams or graphs are present in the provided image which would require additional explanation. This transcription can be used as a part of an educational exercise on calculating deflection in materials under load.

Given, Shaft diameter is 0.75 inch Length of shaft is 13 inch Axial force is 1600 N Required:…

Answered: Determine the deflection in inches of a…

Determine the deflection in inches of a .75" diameter steel shaft 13" long subject to an axial force of 1600-N (E = 205-GPa) A/

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Slope and Deflection

The slope in a deflected beam is described as an angle in radians made by the tangent of the section with the original axis of the beam. The deflection at any point on the axis of the beam is defined as the lateral displacement of the point before and after loading.

Question

please help

**Exercise: Calculating Deflection in a Steel Shaft under Axial Load**

**Objective:**
Determine the deflection in inches of a 0.75" diameter steel shaft that is 13" long, subject to an axial force of 1600 N. The modulus of elasticity (E) for the steel is given as 205 GPa.

**Details:**

- **Shaft Diameter (d):** 0.75 inches
- **Shaft Length (L):** 13 inches
- **Axial Force (P):** 1600 N
- **Modulus of Elasticity (E):** 205 GPa (Gigapascals)

**Procedure:**

- To find the deflection (Δ) of the steel shaft, we will use the formula for axial deformation:
\[
\Delta = \frac{{P \cdot L}}{{A \cdot E}}
\]

Where:
- \( P \) is the axial force.
- \( L \) is the length of the shaft.
- \( A \) is the cross-sectional area of the shaft.
- \( E \) is the modulus of elasticity.

- First, we need to convert all measurements to consistent units (preferably calculating the area in square meters if the force is in Newtons and modulus of elasticity in Pascals).

- Calculate the cross-sectional area (A) of the shaft:
\[
A = \pi \left( \frac{d}{2} \right)^2
\]
Convert d to meters first if required for consistent units with E in Pascals.

Box for calculations:
\[ \Delta = \frac{PL}{AE} \]

By following the outlined steps, the user should be able to accurately determine the deflection of the shaft in response to the given force.

(Note: The figure box for calculation is meant for students to input their answers or for an image showing the calculation steps if this is part of an online educational tool).

---

No diagrams or graphs are present in the provided image which would require additional explanation. This transcription can be used as a part of an educational exercise on calculating deflection in materials under load.

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