Determine the currents and voltages across all the resistances indicated in the circuit shown infigure below.320wwwww8264 V24216260120wwwwwwww

Answered: Determine the currents and voltages…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Related questions

Question

Determine the currents and voltages across all the resistances indicated in the circuit shown in
figure below.
320
www
ww
82
64 V
242
162
60
120
www
ww
www

Expert Solution

Step 1

Given:

Step 2

There will be no current in the $32 Ω$ resistance because a short circuit is in parallel with $32 Ω$ .

$6 Ω$ and $12 Ω$ are in parallel. So the equivalent will be:

$\frac{6 \times 12}{6 + 12} = 4 Ω$

So the circuit diagram will be like:

Apply mesh analysis:

For loop-1

$- 64 + 4 I_{1} + 24 (I_{1} - I_{2}) = 0 28 I_{1} - 24 I_{2} = 64 7 I_{1} - 6 I_{2} = 16 . . . . (1)$

For loop-2:

$24 (I_{2} - I_{1}) + 8 (I_{2} - I_{3}) + 4 (I_{2} - I_{3}) = 0 24 (I_{2} - I_{1}) + 12 (I_{2} - I_{3}) = 0 2 (I_{2} - I_{1}) + (I_{2} - I_{3}) = 0 - 2 I_{1} + 3 I_{2} - I_{3} = 0 . . . . (2)$

For loop-3:

$12 (I_{3} - I_{2}) + 8 I_{3} + 16 I_{3} = 0 12 (I_{3} - I_{2}) + 24 I_{3} = 0 (I_{3} - I_{2}) + 2 I_{3} = 0 - I_{2} + 3 I_{3} = 0 . . . . . . (3)$

On solving above equations:

$I_{1} = 6.4 A I_{2} = 4.8 A I_{3} = 1.6 A$

Step by step

Solved in 3 steps with 2 images

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions