Answered: Determine the Cross-sectional Area and…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Determine the Cross-sectional Area and Volume of Cylindrical Object Measure diameter with a micrometer and the height with a vernier caliper. Where A = π r^2 and V = π r^2 h

0.01mm
0-25 mm
05 10
25
20
15
Cylinder -diameter

Expert Solution

Step 1

Given that,

the pitch scale reading is $P . S . R = 12 (m m)$

Circular scale reading is $C . S . R = 22$

Least count is

$L . C = 0.01 (m m)$

So the diameter of the cylinder is

$\begin{array}{rcl} D & = & P . S . R + C . S . R \times L . C \\ = & 12 (m m) + 22 \times 0.01 (m m) \\ = & 5.22 (m m) \end{array}$

Then the radius will be

$r = \frac{D}{2} = 2.61 (m m)$

For vernier scale,

the main scale reading is $M . S . R = 5 (c m)$

Verner scale reading is $V . S . R = 5$

Least count is $L . C = \frac{0.1 (c m)}{10} = 0.01 (c m)$

So the height of the object is

$\begin{array}{rcl} h & = & M . S . R + V . S . R \times L . C \\ = & 5 (c m) + 5 \times 0.01 (c m) \\ = & 5.05 (c m) \end{array}$

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