Determine the concentration of DCPIP to oxidize the ascorbic acid (5 ml) Data Given: -standard solution of vitamin C (10 mg/ml) -A solution of DCPIP (0.01 M) -27 ml of DCPIP solution was used -One mole of DCPIP = 268.1g -One mole of vitamin C (ascorbic acid) = 176.12g Determination of vitamin C in fruit juice samples Use the concentration of DCPIP that find on Part A to find concentration of vitamin c in fruit juice sample. Data Given : -Titrate 10 ml fruit juice with DCPIP. -2.70 ml of DCPIP was used in the experiment.

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Part A Standardization of DCPIP
Determine the concentration of DCPIP to oxidize the ascorbic acid (5 ml)
Data Given :
-standard solution of vitamin C (10 mg/ml)
-A solution of DCPIP (0.01 M)
-27 ml of DCPIP solution was used
-One mole of DCPIP = 268.1g
-One mole of vitamin C (ascorbic acid) = 176.12g
Determination of vitamin C in fruit juice samples
Use the concentration of DCPIP that find on Part A to find concentration of vitamin c in fruit juice
sample.
Data Given :
-Titrate 10 ml fruit juice with DCPIP.
-2.70 ml of DCPIP was used in the experiment.
Transcribed Image Text:Part A Standardization of DCPIP Determine the concentration of DCPIP to oxidize the ascorbic acid (5 ml) Data Given : -standard solution of vitamin C (10 mg/ml) -A solution of DCPIP (0.01 M) -27 ml of DCPIP solution was used -One mole of DCPIP = 268.1g -One mole of vitamin C (ascorbic acid) = 176.12g Determination of vitamin C in fruit juice samples Use the concentration of DCPIP that find on Part A to find concentration of vitamin c in fruit juice sample. Data Given : -Titrate 10 ml fruit juice with DCPIP. -2.70 ml of DCPIP was used in the experiment.
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