Determine the concatenated transformation matrix for mirroring an object about the plane given by 7x + 3y – 2z + 5 = 0
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- The vertical distance between eye level and the ground for a certain swimmer, who is standing upright, is 1.55 m. If the swimmer is standing 2.00 m from the edge of a 2.50-m-deep swimming pool, how far from the base of the pool will the swimmer be able to see a coin that is at the bottom of the pool? The swimmer is represented by the upward directed arrow in the diagram, and the distance between the base of the pool and the coin is “d”. The index of refraction of water is 1.33. a. 1.55 m b. 0.950 m c. 1.85 m d. 2.15 m e. 1.25 mIn order to identify an unknown material you are asked to solve for the critical angle of the material. In order to test this you set up a beam of light that strikes the unknown substance from air (n = 1.0) at an angle of 30° with respect to the normal. It continues on in the substance at an angle of 23° with respect to the normal. What is the critical angle for the unknown substance? 51° 55° 60° 63°A ray of light crosses the boundary between some substance with n = 1.54 and air, going from the substance into air. If the angle of incidence is 29◦ what is the angle of refraction? Calculate to 1decimal.
- A light ray is incident on the outer surface of the lucite at an angle of 37.8 degrees with the normal. Find the angle the transmitted ray makes with the normal.A plane wavefront is incident on a concave mirror of radius of curvature R. The radius of the refracted wavefront will be: (a) 2R (b) R (c) R 2 (d) 4Let IB and OB be distances from the plane mirror to the image and object, respectively. Show that IB = OB. Prove that image and object have the same size.