Determine the acceleration in each case, match the answers with questions. ◆ A car is moving to the right with a constant speed of 20 m/s for 5.0 s. A car is going to the right, from rest to 20 m/s in 5.0 s. A car is going to the right, from 20 m/s to rest in 5.0 s. A. acceleration = 4.0 m/s² B. acceleration = 0 C. acceleration = - 4.0 m/s² D. acceleration = 100 m/s² E. acceleration = - 100 m/s²
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
![The motion of a car on a track is shown below. What can you say about its velocity and acceleration? Select all apply.
ооо
00
Motion
Detector
14=3s
X4
13=2s MOD
e
X3
The velocity is positive.
The velocity is negative.
The velocity is zero
The acceleration is positive.
The acceleration is negative.
The acceleration is zero.
t₂ = 1s
X₂
t₁ = 0₂
X₁
Positive x
direction](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6c19b30f-6bcf-4092-885c-134d7797f5c5%2F776a9f6e-a98d-4f8b-ae05-2a9b3be4299a%2Fisdywj_processed.png&w=3840&q=75)
![Determine the acceleration in each case, match the answers with questions.
A car is moving to the right with a constant speed of 20 m/s for 5.0 s.
A car is going to the right, from rest to 20 m/s in 5.0 s.
+
A car is going to the right, from 20 m/s to rest in 5.0 s.
A. acceleration = 4.0 m/s²
B. acceleration = 0
C. acceleration = - - 4.0 m/s²
D. acceleration = 100 m/s²
E. acceleration = -
100 m/s²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6c19b30f-6bcf-4092-885c-134d7797f5c5%2F776a9f6e-a98d-4f8b-ae05-2a9b3be4299a%2Fdd8ewad_processed.png&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Step by step
Solved in 3 steps with 3 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
![College Physics](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
![University Physics (14th Edition)](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
![Introduction To Quantum Mechanics](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
![College Physics](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
![University Physics (14th Edition)](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
![Introduction To Quantum Mechanics](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
![Physics for Scientists and Engineers](https://www.bartleby.com/isbn_cover_images/9781337553278/9781337553278_smallCoverImage.gif)
![Lecture- Tutorials for Introductory Astronomy](https://www.bartleby.com/isbn_cover_images/9780321820464/9780321820464_smallCoverImage.gif)
![College Physics: A Strategic Approach (4th Editio…](https://www.bartleby.com/isbn_cover_images/9780134609034/9780134609034_smallCoverImage.gif)