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- You add 28 g of ice (H2O) at 0°C to 179 g of H20 (I) at 63°C at a constant pressure of 1.01 kPa. Calculate the final temperature in K. [AfusH°(H20) = 6.01 kJ mol""; Tfus=273.15 K; Cp.m(H20,)=75.3 J mol Kl; m(H20)=18.02 u].A student determines the molar mass of a liquid unknown by the method used in thisexperiment. She found that the equilibrium temperature of a mixture of ice and water was1.0°C on her thermometer. When she added 12.3 g of her unknown sample to the mixture, thetemperature, after thorough stirring, fell to -4.0°C. She then poured off the solution through ascreen into a beaker. The mass of the solution was 93.4 g. Kf = 1.86°C/m What was the molality of the unknown solution? ______________ m How much unknown liquid was in the decanted solution? ______________ gHow much water was in the decanted solution? ______________ gWhat did she find to be the molar mass of the unknown liquid, assuming she made thecalculation properly?______________ g3. Acetylene (C2H2), which is used for industrial welding, is transported in pressurized cylinders. Its vapor pressure at various temperatures is given in the following table. Plot the data and use your graph to estimate the vapor pressure of acetylene at 293 K. Then use your graph to determine the value of AHvap for acetylene. How much energy is required to vaporize 2.00 g of acetylene at 250 K? T/(K) 145 155 175 200 225 250 300 Р (тm Hg) 1.3 7.8 32.2 190 597 1370 5093
- A can of hair spray with a pressure of 3.0 atm at 25.0°F is exposed to heat. Should the new temperature become 35.0°C, which of the following solutions computes for the new pressure in kPa? (3.0 atm)(269.26 К) (308.15 K) 101.325 kPa ... a. P2 = = 270 kPa 1 atm (3.0 atm) (298.15 К) 101.325 kPa b. P2 = = 290 kPa (308.15 K) 1 atm (3.0 atm)(308.15 К) (269.26 K) 101.325 kPa c. P2 = = 350 kPa 1 atm ((3.0 atm)(308.15 K)' 101.325 kPay d. P2 = 310 kPa (298.15 K) 1 atm3. Using the definition of isothermal compressibility (K): 1 (av -= (+)₂, ӘР T Solve for K for an ideal gas. KTemperature 120 LEG 'E LEG 'D tabla t pe 000 Orm with temperatur 05 09 40 300 (69 LEG 'B' 008 000 009 LEG A' at is the botie 000 000 Heat in Calories According to the diagram, during a phase change the temperature - F increases TO G decreases H fluctuates Jremains constant adua alrt to in ce occnie s 1ub (cepa) 300 90 coriqacmte a bn
- The following information is given for silicon at 1 atm: Tb = 2355.00°C Tm = 1410.00°C Specific heat solid = 0.7110 Specific heat liquid A 44.60 g sample of solid silicon is initially at 1384.00°C. If the sample is heated at constant pressure (P = 1 atm), the temperature of the sample to 1536.00°C. = 0.9080 AHvap (2355.00°C) = 10580 J/g AHfus (1410.00°C) = 1653 J/g J g.°C J g.˚C kJ of heat are needed to raisePlease calculate the energy of inward movement of chloride ions given: Na+ F=23100 cal/V*mol Vm = -60mV R =2cal/mol*K T = 300K Inside 50mM Outside 150mM A. -2051.2 cal/mol B. 2051.2 cal/mol C. -727cal/mol D. 727cal/molR = 0.08205 L atm mol-1 K-1 T(K) = T (°C) + 273.15
- O ||| 2 rosoft C W Microsoft Use the observation in the first column to answer the question in the second column. Microsoft 6.52.210... esc OSTATES OF MATTER Understanding the connection between vapor pressure, boiling... At 1 atm pressure, Substance E boils at 111. °C and Substance F boils at 86. °C. observation At 34 °C, Substance A has a vapor pressure of 105. torr and Substance B has a vapor pressure of 145. torr. The enthalpy of vaporization of Substance C is bigger than that of Substance D. Explanation ! 1 C 2 Check 9,088 W 280 Which has a higher enthalpy of vaporization? Substance E Substance F Neither, E and F have the same enthalpy of vaporization. It's impossible to know without more information. Which has a higher boiling point? Substance A Substance B Neither, A and B have the same boiling point. It's impossible to know without more information. Which has the higher boiling point? #3 question Substance C Substance D Neither, C and D have the same boiling point. It's…Trouton's rule states that the molar enthalpy of Chemical AHvap Boiling AHfus Compound vaporization of a liquid that does not have strong molecular interactions such as hydrogen bonding or ion-ion attractions is given by formula (kJ-mol-1) point (K) (kJ-mol¬1) chloromethane CH;CI 21.40 249.06 6.43 AH vap (85 J. K-1. mol-') To H,0 water 40.65 373.15 6.01 where T, is the normal boiling point of the liquid hydrogen H,S 18.67 213.60 18.67 in kelvins. sulfide Apply Trouton's rule to estimate the value of AHvap for these compounds. chloromethane: AHvap kJ/molWhich one of the following is TRUE about AH°ffor the substances given? a. AH°ffor Br2(e) = 0 O b. AH°; for He(e) = 0 O c. AH°ffor N2(e) > O O d. AH°ffor O(g) < 0 O e. None of these is true
