Determine result of the operation or contents of the destination, machine code, and the address ranger after determining the machine code. If 32-bits register is needed and only 16-bits are given, append multiple 'F on the most significant bits before performing the operation stated. For displacement and immediate value, use hexadecimal. Write the displacement right after the modregR/M. Use single space in between bytes. Example: Contents of the destination: DX=1234 or 12345=AA 12346=B8 Machine Code: 1001001 01111100 AB CD EE FF (opcode.d.w modregR/M displacement) Address Range: 12345-12346 Instruction type: data transfer (small letters only) 5(4)JPG ... AX =ECDEH DX =9BD7H SS = 9EFBH SI = CAAEH IP = CAC9H BX =AF4CH CS =CA8FH BP - AB79H ES = B3D8H |CX =BA04H DI = 8FA7H SP = ECDAH DS =A9FDH ADC [SI+FFEEH], ESP 3BJPG PHY. PHY. PHY. PHY. PHY. ADD ADD ADD ADD ADD D021CH FEH C13CAH CDH BF28SH 54H BCD27H BEH B7F8FH 11H D021DH DCH C13CBH E7H BF284H 03H BCD28H OSH B7FBEH 84H D021EH OSH C13CCH OSH BF283H 05H BCD29H 87H B7F8DH 52H D021FH FDH C13CDH ACH BF282H 98H BCD2AH A1H 87F8CH AIH D0220H 76H C1SCEH A1H BF281H 76H BCD2BH 52H B7F8BH 27H D0221H 54H C13CFH 52H BF28OH FEH BCD2CH 11H B7F8AH E7H D0222H 32H C13DOH 11H BF27FH DCH BCD2DH 84H B7F89H 04H Contents of the destination: Blank 1 Machine Code:Blank 2 Address Range: Blank 3 Instruction type: Blank 4
Determine result of the operation or contents of the destination, machine code, and the address ranger after determining the machine code. If 32-bits register is needed and only 16-bits are given, append multiple 'F on the most significant bits before performing the operation stated. For displacement and immediate value, use hexadecimal. Write the displacement right after the modregR/M. Use single space in between bytes. Example: Contents of the destination: DX=1234 or 12345=AA 12346=B8 Machine Code: 1001001 01111100 AB CD EE FF (opcode.d.w modregR/M displacement) Address Range: 12345-12346 Instruction type: data transfer (small letters only) 5(4)JPG ... AX =ECDEH DX =9BD7H SS = 9EFBH SI = CAAEH IP = CAC9H BX =AF4CH CS =CA8FH BP - AB79H ES = B3D8H |CX =BA04H DI = 8FA7H SP = ECDAH DS =A9FDH ADC [SI+FFEEH], ESP 3BJPG PHY. PHY. PHY. PHY. PHY. ADD ADD ADD ADD ADD D021CH FEH C13CAH CDH BF28SH 54H BCD27H BEH B7F8FH 11H D021DH DCH C13CBH E7H BF284H 03H BCD28H OSH B7FBEH 84H D021EH OSH C13CCH OSH BF283H 05H BCD29H 87H B7F8DH 52H D021FH FDH C13CDH ACH BF282H 98H BCD2AH A1H 87F8CH AIH D0220H 76H C1SCEH A1H BF281H 76H BCD2BH 52H B7F8BH 27H D0221H 54H C13CFH 52H BF28OH FEH BCD2CH 11H B7F8AH E7H D0222H 32H C13DOH 11H BF27FH DCH BCD2DH 84H B7F89H 04H Contents of the destination: Blank 1 Machine Code:Blank 2 Address Range: Blank 3 Instruction type: Blank 4
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
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![Determine result of the operation or contents of the destination, machine code, and the address ranger after determining the
machine code. If 32-bits register is needed and only 16-bits are given, append multiple F on the most significant bits before
performing the operation stated. For displacement and immediate value, use hexadecimal. Write the displacement right after
the modregR/M. Use single space in between bytes.
Example:
Contents of the destination: DX=1234 or 12345=AA,12346=BB
Machine Code: 1001001 01111100 AB CD EE FF (opcode,d.w modregR/M displacement)
Address Range: 12345-12345
Instruction type: data transfer (small letters only)
5(4)JPG
...
AX =ECDEH
SS = 9EFBH
ES = B3D8H
DI = 8FA7H
SI = C4AEH
ВP АВ79H
SP = ECDAH
DX =9BD7H
IP = CAC9H
BX =AF4CH
CS =CA8FH
CX =BA04H
DS =A9FDH
ADC [SI+FFEEH], ESP
3BJPG
PHY.
PHY.
PHY.
PHY.
PHY.
ADD
ADD
ADD
ADD
ADD
C13CAH CDH
C13CBH
C13CCH
D021CH
FEH
BF285H
54H
BCD27H
BEH
B7FBFH
11H
D021DH
DCH
E7H
BF284H
03H
BCD28H
OSH
B7FBEH
84H
D021EH
OSH
OSH
BF283H
05H
BCD29H
87H
B7F8DH
52H
C13CDH ACH
C13CEH
D021FH
FDH
BF282H
98H
BCD2AH
A1H
B7F8CH
A1H
D0220H
76H
A1H
BF281H
76H
BCD2BH
52H
B7F8BH
27H
D0221H
54H
C13CFH
52H
BF280H
FEH
BCD2CH
11H
B7F8AH
E7H
D0222H
32H
C13DOH
11H
BF27FH
DCH
BCD2DH
84H
B7F89H
04H
Contents of the destination: Blank 1
Machine Code:Blank 2
Address Range: Blank 3
Instruction type: Blank 4
Blank 1 Add your answer
Blank 2 Add your answer
Blank 3
Add your answer
Blank 4
Add your answer](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3059efa6-d370-4111-a684-c1c30f3d6bec%2F49d9c1e5-7ebd-4f51-8ab2-6841dbaf2a78%2F4swi98_processed.png&w=3840&q=75)
Transcribed Image Text:Determine result of the operation or contents of the destination, machine code, and the address ranger after determining the
machine code. If 32-bits register is needed and only 16-bits are given, append multiple F on the most significant bits before
performing the operation stated. For displacement and immediate value, use hexadecimal. Write the displacement right after
the modregR/M. Use single space in between bytes.
Example:
Contents of the destination: DX=1234 or 12345=AA,12346=BB
Machine Code: 1001001 01111100 AB CD EE FF (opcode,d.w modregR/M displacement)
Address Range: 12345-12345
Instruction type: data transfer (small letters only)
5(4)JPG
...
AX =ECDEH
SS = 9EFBH
ES = B3D8H
DI = 8FA7H
SI = C4AEH
ВP АВ79H
SP = ECDAH
DX =9BD7H
IP = CAC9H
BX =AF4CH
CS =CA8FH
CX =BA04H
DS =A9FDH
ADC [SI+FFEEH], ESP
3BJPG
PHY.
PHY.
PHY.
PHY.
PHY.
ADD
ADD
ADD
ADD
ADD
C13CAH CDH
C13CBH
C13CCH
D021CH
FEH
BF285H
54H
BCD27H
BEH
B7FBFH
11H
D021DH
DCH
E7H
BF284H
03H
BCD28H
OSH
B7FBEH
84H
D021EH
OSH
OSH
BF283H
05H
BCD29H
87H
B7F8DH
52H
C13CDH ACH
C13CEH
D021FH
FDH
BF282H
98H
BCD2AH
A1H
B7F8CH
A1H
D0220H
76H
A1H
BF281H
76H
BCD2BH
52H
B7F8BH
27H
D0221H
54H
C13CFH
52H
BF280H
FEH
BCD2CH
11H
B7F8AH
E7H
D0222H
32H
C13DOH
11H
BF27FH
DCH
BCD2DH
84H
B7F89H
04H
Contents of the destination: Blank 1
Machine Code:Blank 2
Address Range: Blank 3
Instruction type: Blank 4
Blank 1 Add your answer
Blank 2 Add your answer
Blank 3
Add your answer
Blank 4
Add your answer
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