Determine in how many ways you can choose the digits in (123)10, (91929394) 10 in a way that (x₁ + x₂ + x3)(Y₁+ y2 + Y3 + Y₁) = 77.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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1. Determine in how many ways you can choose the digits in
(Y1Y2Y394) 10
in a way that
(x₁ + x₂ + x3)(y₁ + y2 + Y3 + Y₁) = 77.
1 (T1T2X3)10,
Transcribed Image Text:1. Determine in how many ways you can choose the digits in (Y1Y2Y394) 10 in a way that (x₁ + x₂ + x3)(y₁ + y2 + Y3 + Y₁) = 77. 1 (T1T2X3)10,
Expert Solution
Introduction

As per the question we are given a diophantine equation as :

(x1 + x2 + x3) (y1 + y2 + y3 + y4) = 77

Now we have to find the total number of ways to choose the digits in (x1x2x3)10 (y1y2y3y4)10 i.e. the integer values of x1 , x2 , x3 , y1 , y2 , y3 , y4 between and such that the above equation is satisfied.

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