Determine if the series converges or diverges. Give a reason for your answer. Σ n=1 4 6 + Inn Does the series converge or diverge? OA. The limit comparison test with B. The limit comparison test with O c. The limit comparison test with D. The limit comparison test with n=1 n=1 n=1 ∞ 3|→ shows that the series diverges. 1 2n 1 shows that the series diverges. shows that the series converges. shows that the series converges.
Determine if the series converges or diverges. Give a reason for your answer. Σ n=1 4 6 + Inn Does the series converge or diverge? OA. The limit comparison test with B. The limit comparison test with O c. The limit comparison test with D. The limit comparison test with n=1 n=1 n=1 ∞ 3|→ shows that the series diverges. 1 2n 1 shows that the series diverges. shows that the series converges. shows that the series converges.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![Determine if the series converges or diverges. Give a reason for your answer.
\[
\sum_{{n=1}}^{\infty} \frac{4}{6 + \ln n}
\]
---
Does the series converge or diverge?
- **A.** The limit comparison test with \(\sum_{{n=1}}^{\infty} \frac{1}{n}\) shows that the series diverges.
- **B.** The limit comparison test with \(\sum_{{n=1}}^{\infty} \frac{1}{2^n}\) shows that the series diverges.
- **C.** The limit comparison test with \(\sum_{{n=1}}^{\infty} \frac{1}{n}\) shows that the series converges.
- **D.** The limit comparison test with \(\sum_{{n=1}}^{\infty} \frac{1}{2^n}\) shows that the series converges.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12e6f1d1-a59b-426e-b55c-5778644eb2da%2F2721e147-0d07-49cb-8469-aff7449f62a7%2Fz609rxe_processed.png&w=3840&q=75)
Transcribed Image Text:Determine if the series converges or diverges. Give a reason for your answer.
\[
\sum_{{n=1}}^{\infty} \frac{4}{6 + \ln n}
\]
---
Does the series converge or diverge?
- **A.** The limit comparison test with \(\sum_{{n=1}}^{\infty} \frac{1}{n}\) shows that the series diverges.
- **B.** The limit comparison test with \(\sum_{{n=1}}^{\infty} \frac{1}{2^n}\) shows that the series diverges.
- **C.** The limit comparison test with \(\sum_{{n=1}}^{\infty} \frac{1}{n}\) shows that the series converges.
- **D.** The limit comparison test with \(\sum_{{n=1}}^{\infty} \frac{1}{2^n}\) shows that the series converges.
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