Determine if the differential equation (y^2 - 2xy + 6x)dx - (x^2 - 2xy + 2)dy = 0 is exact. If exact, which of the following is the particular solution when y(-2) = 1 ? If the equation is not exact, write the capital letter NE. A. x²y - xy² + 3x - 2y +4 =0 B. x²y - xy² + 3x²-2y -4 = 0 с. ху²-х³y +3x2-2=0 2 D. xy² - x²y + 3x²³ - 2y -4 = 0 Е. хуч-хчу + 3x2-2y -13=0 F. xy²-x²y + 3x² - 2y + 4 = 0

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