A large university is interested in learning about the average time it takesstudents to drive to campus. The university sampled 238 students and asked eachto provide the amount of time they spent traveling to campus. This variable,travel time, was then used conduct a test of hypothesis. The goal was todetermine if the average travel time of all the university's students differed from20 minutes. Find the large-sample rejection region for the test of interest to thecollege when using a level of significance of 0.05.Reject Ho if z < -1.96 or z> 1.96.Reject Ho if z> 1.645.Reject Ho if z < -1.645 or z> 1.645.Reject Ho if z < -1.96.

It is given that Claim: The average travel time of all the university’s students differed from 20…

Answered: determine if the average travel time of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

9. In case of two samples test: If z value is in the rejection region, the decision is: "reject the alternative hypothesis" Select one: True False
10.
The average retirement age in America is 66 years old. Do small business owners retire at an older average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 63, 74, 59, 64, 74, 60, 71, 67, 65, 70, 63 What can be concluded at the the � = 0.05 level of significance level of significance? For this study, we should use The null and alternative hypotheses would be: �0: �1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is � Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly older than 66 at � = 0.05, so there is sufficient evidence to conclude that the population mean retirement age for small business owners is older than 66. The data suggest…
You may need to use the appropriate appendix table or technology to answer this question. The following results are for independent random samples taken from two populations. Sample 1 Sample 2 n1 = 20 n, = 30 X1 = 22.7 X2 = 20.1 s, = 2.3 2 = 4.6 (a) What is the point estimate of the difference between the two population means? (Use x, - x,.) 2.72 (b) What is the degrees of freedom for the t distribution? (Round your answer down to the nearest integer.) 48 (c) At 95% confidence, what is the margin of error? (Round your answer to one decimal place.) 1.9 (d) What is the 95% confidence interval for the difference between the two population means? (Use x, - Round your answers to one decimal place.) .6 to 4.4
9. Summarize the results from an analysis (two-way ANOVA) performed on the data graphed below. Assume big differences are significant and trivial differences are not. Mean y 22.5- 20.0- 17.5 15.0 12.5 10.0
An online store chooses an SRS of 101 customers from its list of all people who have bought something from the store in the last year. It asks those selected how satisfied they are with the store’s website. If it selected two SRSs of 100 customers at the same time, the two samples would give somewhat different results. Is this variation a source of sampling error or of nonsampling error? Explain why. Would the survey’s announced margin of error take this source of error into account.
8.What is the sample variance and the estimated standard error for a sample of n = 9 scores with SS = 72? a. s2= 9 and sM = 3 c. s²= 3 and sM = 3 b. s? = 9 and SM = 1 d. s2 = 3 and sM= 1 %3D
A simple random sample of 35 pages from Merriam-Webster's Collegiate Dictionary is obtained. The numbers of words defined on those pages are found with the following results: the sample size is 35, the sample mean is 53.3 words per page, the sample standard is 15.7 words per page. Given that this dictionary has 1459 page with defined words, the claim that there are more than 70 000 defined words is equivalent to the claim that the mean number of words per page is greater than 48.0 words. Assume a normally distributed population. Use a 0.05 significance level to test the claim that the mean number of words per page is greater than 48.0 words.
How many degrees of freedom is there for between group variance for an ANOVA on 10 groups with 20 samples in each group
There are two samples. One is a group of 8 athletes who practice and the other is a group of 5 athletes who do not practice. The mean for group 1 is 92.4 and the standard deviation is 5.83. For group 2, the mean is 81.3 and the standard deviation 7.85. the coach thinks the true mean for the athletes who did not practice is more that 8 points smaller than those who did practice. a) make the null and alternative hypotheses. calculate the test statistic and give an explanation as to why you chose this test statistic.
In our ANOVA calculation, we want our within-group variation to be higher than the between-group variation. True or False?
A simple random sample of 35 pages from Merriam-Webster's Collegiate Dictionary is obtained. The numbers of words defined on those pages are found with the following results: the sample size is 35, the sample mean is 53.3 words per page, the sample standard is 15.7 words per page. Given that this dictionary has 1459 page with defined words, the claim that there are more than 70 000 defined words is equivalent to the claim that the mean number of words per page is greater than 48.0 words. Assume a normally distributed population. Use a 0.05 significance level to test the claim that the mean number of words per page is greater than 48.0 words.

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