Determine and o u=78, o=18, n = 36 from the given parameters of the

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Determine u and o from the given parameters of the population and sample size U = 78 O = 18 N = 36
**Instruction: Determining Sample Mean and Standard Deviation**

Given the parameters of the population, calculate the sample mean \((\mu_{\bar{x}})\) and sample standard deviation \((\sigma_{\bar{x}})\).

**Population Parameters:**
- Population Mean (\(\mu\)) = 78
- Population Standard Deviation (\(\sigma\)) = 18
- Sample Size (\(n\)) = 36

**Calculation:**

1. **Sample Mean (\(\mu_{\bar{x}}\))**  
   - Since the sample mean is the same as the population mean:
     \[
     \mu_{\bar{x}} = \mu = 78
     \]

2. **Sample Standard Deviation (\(\sigma_{\bar{x}}\))**  
   - Calculated using the formula:
     \[
     \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}}
     \]
   - Substituting the given values:
     \[
     \sigma_{\bar{x}} = \frac{18}{\sqrt{36}} = \frac{18}{6} = 3
     \]

**Conclusion:**

- Sample Mean \((\mu_{\bar{x}})\) = 78
- Sample Standard Deviation \((\sigma_{\bar{x}})\) = 3

**Visual Explanation:**

- There are no graphs or diagrams included in the given text. The information appears in a simple textual format with two empty boxes indicating spaces where these calculated values should be entered.
Transcribed Image Text:**Instruction: Determining Sample Mean and Standard Deviation** Given the parameters of the population, calculate the sample mean \((\mu_{\bar{x}})\) and sample standard deviation \((\sigma_{\bar{x}})\). **Population Parameters:** - Population Mean (\(\mu\)) = 78 - Population Standard Deviation (\(\sigma\)) = 18 - Sample Size (\(n\)) = 36 **Calculation:** 1. **Sample Mean (\(\mu_{\bar{x}}\))** - Since the sample mean is the same as the population mean: \[ \mu_{\bar{x}} = \mu = 78 \] 2. **Sample Standard Deviation (\(\sigma_{\bar{x}}\))** - Calculated using the formula: \[ \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \] - Substituting the given values: \[ \sigma_{\bar{x}} = \frac{18}{\sqrt{36}} = \frac{18}{6} = 3 \] **Conclusion:** - Sample Mean \((\mu_{\bar{x}})\) = 78 - Sample Standard Deviation \((\sigma_{\bar{x}})\) = 3 **Visual Explanation:** - There are no graphs or diagrams included in the given text. The information appears in a simple textual format with two empty boxes indicating spaces where these calculated values should be entered.
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