14Determine (a) the x6 test statistic, (b) the degrees of freedom, (c) the P-value, and (d) test the hypothesis at the a = 0.05 level of significance.Observed437121439386Expected1.625.3151.6 404.3 404.3Ho: The random variable X is binomial with n = 4, p = 0.8H,: The random variable X is not binomial with n = 4, p = 0.8Click the icon to view the chi-square distribution table.(a) x3=(Round to two decimal places as needed.)(b) There aredegrees of freedom.(c) The P-value is(d) What is the conclusion of the test at the a = 0.05 level of significance?the null hunothesic becauce the Pvvalue isThereovidence that the random variable Y ic not hinomial with n - 4. n -08

Name: 14Determine (a) the x6 test statistic, (b) the degrees of freedom, (c
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: 14Determine (a) the x6 test statistic, (b) the degrees of freedom, (c) the P-value, and (d) test the hypothesis at the a = 0.05 level of significance.Observed437121439386Expected1.625.3151.6 404.3 404.3Ho: The random variable X is binomial with n =

a. The null and alternative hypotheses are, H0: The random variable X is binomial with n = 4, p…

Math

Statistics

Determine (a) the xở test statistic, (b) the degrees of freedom, (c) the P-value, and (d) test the hypothesis at the a = 0.05 level of significance. X Observed Expected 1 2 3 4 4 37 121 439 386 1.6 25.3 151.6 404.3 404.3 Ho: The random variable X is binomial with n= 4, p=0.8 H,: The random variable X is not binomial withn=4, p= 0.8 E Click the icon to view the chi-square distribution table. (a) xỗ = O (Round to two decimal places as needed.) (b) There are degrees of freedom. (c) The P-value is (d) What is the conclusion of the test at the a= 0.05 level of significance? v the n ll hunothncie boonuse the D ualue ie than Thore V ovidonce that the rondom uarinhlo V ie not hinomial uarith n-4 n-n8

Determine (a) the xở test statistic, (b) the degrees of freedom, (c) the P-value, and (d) test the hypothesis at the a = 0.05 level of significance. X Observed Expected 1 2 3 4 4 37 121 439 386 1.6 25.3 151.6 404.3 404.3 Ho: The random variable X is binomial with n= 4, p=0.8 H,: The random variable X is not binomial withn=4, p= 0.8 E Click the icon to view the chi-square distribution table. (a) xỗ = O (Round to two decimal places as needed.) (b) There are degrees of freedom. (c) The P-value is (d) What is the conclusion of the test at the a= 0.05 level of significance? v the n ll hunothncie boonuse the D ualue ie than Thore V ovidonce that the rondom uarinhlo V ie not hinomial uarith n-4 n-n8

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Fill in the blank by using drag and drop one of the following answers (some options will not be used): Part 1: Given that Z is a standard normal random variable, compute the following probabilities: a) P(Z ≤ 2.2) = b) P(Z >-0.6) = c) P(Z < -2.36) = d) P(Z < ) = 0.6179 Part 2: The Italian National Bank is reviewing its current account service charges and interest payment procedures. The average daily balance is Normally distributed, with a mean of £490 and a standard deviation of £110, according to the bank. The probability of current users having more than £732 in their accounts is The probability of current users having between £424 and £523 in their accounts is 0.9495 -2.44 0.8849 0.9861 0.7257 0.0091 0.9357 0.3 0.0505 0.8776 0.3436 0.9448 0.0139
N2
Two new machines for producing tires have been proposed by a worker in a manufacture. The manufacture believes there will be no difference in the strength of tires produced by these machines. To test this hypothesis, a sample of 9 tires produced by machine 1 and 7 tires produced by machine 2 were randomly selected. It is known from previous experience that the strength of a tire produced using machine 1 is a normal random variable with standard deviation equals to 3. And the strength of a tire produced using machine 2 is also a normal random variable with standard deviation equals to 4. use the following information to answer the following questions: Machine 1Machine 2 6.5 1.0 6.7 2.5 5.8 3.2 4.9 3.1 5.3 4.5 4.0 5.7 3.1 1.5 5.7 4.3 i. Find the estimated difference mean strength of tires produced using both machines [ X1-X2] . O0.06 ONone of these O-2.18 O2.07 O-0.25
It is believed that 70% of males pass their drivers test in the first attempt, while 65% of females pass the test in the first attempt. A test will be conducted to check whether the proportions are in fact equal. a. State the hypotheses in terms of the appropriate parameter(s)b. Determine if the samples are independent or dependentc. Identify the random variable, and its distribution (either normal or t-distribution), along and explain this choice. d. Identify the test to be used.
Let a be a random variable representing the percentage of protein content for early bloom alfalfa hay. The average percentage protein content of such early bloom alfalfa should be u = 17.2%. A farmer's co-op is thinking of buying a large amount of baled hay but suspects that the hay is from a later summer cutting with lower protein content. A small amount of hay was removed from each bale of a random sample of 50 bales. The average protein content from the samples was determined by a local agricultural college to be -15.8% with a sample standard deviation of S = 5.3%- At a = .05, does this hay have lower average protein content than the early bloom alfalfa?
Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us. Refer to screenshot. (a) Suppose n = 27 and p = 0.23. Can we approximate p̂ by a normal distribution? Why? (Use 2 decimal places.) for the second part the options are: (Yes, no) p̂ (can, cannot) be approximated by a normal random variable because (np exceeds, np and nq do not exceed, nq exceeds, nq does not exceed, both np and nq exceed, np does not exceed) ___________ (fill in blank). What are the values of ?p̂ and ?p̂? (Use 3 decimal places.)
Plz answer all the parts and get thumb up
A computer repair shop has two work centers. The first center examines the computer to see what is wrong and the second center repairs the computer. Let and be random variables representing the lengths of time in minutes to examine a computer () and to repair a computer (). Assume and are independent random variables. Long-term history has shown the following mean and standard deviation for the two work centers: Examine computer, : = 27.3 minutes; = 7.5 minutes Repair computer, : = 90.1 minutes; = 15.3 minutes Let be a random variable representing the total time to examine and repair the computer. Suppose it costs $1.80 per minute to examine the computer and $2.83 per minute to repair the computer. Then is a random variable representing the service charges (without parts). Compute the mean and standard deviation of V. Round your answer to the nearest tenth.
-5 26 28 30 32 33 34 35\ Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of c. P(0.9
For normally distributed random variables, how would one verify the empirical rule percentages using z scores? Multiple choice question. Find P(-2 ≤ Z ≤ 2) from a standard normal table and compare to 68%. Find P(-1 ≤ Z ≤ 1) from a standard normal table and compare to 95%. Find P(-2 ≤ Z ≤ 2) from a standard normal table and compare to 99.7%. Find P(-1 ≤ Z ≤ 1) from a standard normal table and compare to 68%.
Show full answers and steps deriving to the questions being asked in the exercise. Please don’t use R or excel when calculating expected value or variance. Formula calculate required
Two new machines for producing tires have been proposed by a worker in a manufacture. The manufacture believes there will be no difference in the strength of tires produced by these machines. To test this hypothesis, a sample of 9 tires produced by machine 1 and 7 tires produced by machine 2 were randomly selected. It is known from previous experience that the strength of a tire produced using machine 1 is a normal random variable with standard deviation equals to 3. And the strength of a tire produced using machine 2 is also a normal random variable with standard deviation equals to 4. use the following information to answer the following questions: 1. Find the estimated difference mean strength of tires produced using both machines [X-X) 2. What is the value of the test statistic : ii. If p-value was found equal to 0.12, What is the appropriate conclusion?