Determine: 1. Determine total mud volume in surface system in bbl. 2. Total hole volume with drill pipe in the hole. 3. Total circulating system volume.
Determine: 1. Determine total mud volume in surface system in bbl. 2. Total hole volume with drill pipe in the hole. 3. Total circulating system volume.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Q4:B: Given: the Following Data 13%-in. casing 48 Ib/t Casing Data Surface casing: 1,850 ft of 133/8-in (12.415 in ID), 48 Ib/ft Intermediate: 8,643 ft of 958-in. 32.30 Ib/ft (8.681 in ID) Liner: 8,300 to 14,500 ft of 7-in. (6.672 in ID) 20 Ib/ft Hole Data Bit diameter: 61/8-in. Total Depth (TD): 17,800 ft S et Drill String Data Tapered drill string: 5-in. drill pipe (4.276 in ID) 19.50 Ib/ft to 8,000 ft 80001t 312-in., (2.764 in ID) 13.3 1b/ft t016,800 ft 8300 1t 1,000 ft of 43/4-in. OD x 21/4-in. ID Drill collars Surface system: Three pits: 8.5-ft high, 69-ft wide, 23-ft long. In two pits there is 77 in. of mud, and in the remaining pit there is 65 3%ein. drill pipe 13.3 IbAt in. of mud with drill string in hole. Mud weight: 15.3 Ib/gal Mud pumps: Triplex: 612-in. x 12-in., 50 stk/min, at 95% 7-in. liner 20 Ib/t efficiency | —— 9%-in. casing 32.3 b/t 86431t 14,500 ft 6%-in. open hole 16,800 ft 4¥ein. drill collars 46.7 Ib/ft -
![Q4:B:
Given: the Following Data
Casing Data
13%-in. casing 48 Ib/ft
Surface casing: 1,850 ft of 1338-in (12.415 in ID), 48 lb/ft
Intermediate: 8,643 ft of 95/8-in. 32.30 lb/ft (8.681 in ID)
Liner: 8,300 to 14,500 ft of 7-in. (6.672 in ID) 20 lb/ft
1,850 ft
Hole Data
Bit diameter: 61/8-in.
5-in. drill pipe 19.5 lb/ft
Total Depth (TD): 17,800 ft
Drill String Data
96-in. casing 32.3 Ib/ft
Tapered drill string:
5-in. drill pipe (4.276 in ID) 19.50 lb/ft to 8,000 ft
312-in., (2.764 in ID) 13.3 lb/ft to16,800 ft
1,000 ft of 43/4-in. OD x 214-in. ID Drill collars
Surface system:
Three pits: 8.5-ft high, 69-ft wide, 23-ft long. In two pits
there is 77 in. of mud, and in the remaining pit there is 65
in. of mud with drill string in hole.
Mud weight: 15.3 lb/gal
Mud pumps: Triplex: 612-in. x 12-in., 50 stk/min, at 95%
efficiency
8,000 ft
8,300 ft
8,643 ft
32-in. drill pipe 13.3 lb/ft
7-in. liner 20 Ib/ft
14,500 ft
6%-in. open hole
16,800 ft
44-in, drill collars 46.7 Ib/ft
17,800 ft
Determine:
1. Determine total mud volume in surface system in bbl.
2. Total hole volume with drill pipe in the hole.
3. Total circulating system volume.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0f453fe3-1091-4208-941d-396d5d26a65a%2F69d298e2-38a1-464e-8dcb-e65557d100f4%2Fwsfb68i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q4:B:
Given: the Following Data
Casing Data
13%-in. casing 48 Ib/ft
Surface casing: 1,850 ft of 1338-in (12.415 in ID), 48 lb/ft
Intermediate: 8,643 ft of 95/8-in. 32.30 lb/ft (8.681 in ID)
Liner: 8,300 to 14,500 ft of 7-in. (6.672 in ID) 20 lb/ft
1,850 ft
Hole Data
Bit diameter: 61/8-in.
5-in. drill pipe 19.5 lb/ft
Total Depth (TD): 17,800 ft
Drill String Data
96-in. casing 32.3 Ib/ft
Tapered drill string:
5-in. drill pipe (4.276 in ID) 19.50 lb/ft to 8,000 ft
312-in., (2.764 in ID) 13.3 lb/ft to16,800 ft
1,000 ft of 43/4-in. OD x 214-in. ID Drill collars
Surface system:
Three pits: 8.5-ft high, 69-ft wide, 23-ft long. In two pits
there is 77 in. of mud, and in the remaining pit there is 65
in. of mud with drill string in hole.
Mud weight: 15.3 lb/gal
Mud pumps: Triplex: 612-in. x 12-in., 50 stk/min, at 95%
efficiency
8,000 ft
8,300 ft
8,643 ft
32-in. drill pipe 13.3 lb/ft
7-in. liner 20 Ib/ft
14,500 ft
6%-in. open hole
16,800 ft
44-in, drill collars 46.7 Ib/ft
17,800 ft
Determine:
1. Determine total mud volume in surface system in bbl.
2. Total hole volume with drill pipe in the hole.
3. Total circulating system volume.
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