Table 1. Free Fall h(cm ) t1( s ) t2( s ) t3( s ) 40.00.28500.28480.2847 50.00.32090.32040.3201 60.00.35160.35220.3519 70.00.37820.37850.3778 80.00.40360.40390.4044 90.00.42700.42730.4264 solve the question in the image and make sure it is correct 100%L1= 0.3L2 = 0.7 Determination of Acceleration due to Gravity (g)Plot the graph of I versus t2 and determine the value of g1.아-L20.9-0.8-L- L,Slope :mis%3D0.가-0.6-0.5E(m)0.4-g = 4 n²x slope =m/s0.3-0.2-T0.1-46.T? (s)The value of (ggraph) = 4t xslope%3D%3DTaking (gtheoretical = 9.8 m/s'), the percentage error of your result is:gtheoretical Sgraph X 100=Stpearetinal% Error:%3D Part B:Table 2: Simple pendulumTiT2T(Tyg(cm)(s)(s)(s)45.01.3551.3591.35155.01.4901.4921.49365.01.6141.6171.61575.01.7461.7481.74285.01.8511.8501.84995.01.9571.9541.953Average value g =Find the Standard Error:(g-9) ( )(Gi-g) ( )Standard deviation (Og) =n-1Standard Error (og) =%3DResult g + og =

Given: L1=0.3 mL2=0.7 m Introduction: Acceleration due to gravity is the acceleration gained by an…

Answered: Determination of Acceleration due to…

Table 1. Free Fall

h (cm )	t₁ ( s )	t₂ ( s )	t₃ ( s )
40.0	0.2850	0.2848	0.2847
50.0	0.3209	0.3204	0.3201
60.0	0.3516	0.3522	0.3519
70.0	0.3782	0.3785	0.3778
80.0	0.4036	0.4039	0.4044
90.0	0.4270	0.4273	0.4264

solve the question in the image and make sure it is correct 100%

L1= 0.3

L2 = 0.7

Determination of Acceleration due to Gravity (g)
Plot the graph of I versus t2 and determine the value of g
1.아-
L2
0.9-
0.8-
L- L,
Slope :
mis
%3D
0.가-
0.6-
0.5E
(m)
0.4-
g = 4 n²x slope =
m/s
0.3-
0.2-
T
0.1-
4
6.
T? (s)
The value of (ggraph) = 4t xslope
%3D
%3D
Taking (gtheoretical = 9.8 m/s'), the percentage error of your result is:
gtheoretical Sgraph X 100=
Stpearetinal
% Error:
%3D

Part B:
Table 2: Simple pendulum
Ti
T2
T
(Ty
g
(cm)
(s)
(s)
(s)
45.0
1.355
1.359
1.351
55.0
1.490
1.492
1.493
65.0
1.614
1.617
1.615
75.0
1.746
1.748
1.742
85.0
1.851
1.850
1.849
95.0
1.957
1.954
1.953
Average value g =
Find the Standard Error:
(g-9) ( )
(Gi-g) ( )
Standard deviation (Og) =
n-1
Standard Error (og) =
%3D
Result g + og =

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Table 1. Free Fall