Determinar la de Formacion Maxima en el punto c. Metodo Areas de Momento A 2400 KgF 2 + 2 J ㅓ 6 73000155/80 B m Hormigón f·c = 280 kgf/cm E = 15000√√ Seccion de Viga Determinar las reacciones, Metodo Doble Integracion. 2000 KgF c 1800 g/m m + z z 6 Determinar las Reacciones en la viga. Nebdo Areas de Momento. 1500 kgf-m -2500 kg/m 2 c 8 306m 15 60cm
Determinar la de Formacion Maxima en el punto c. Metodo Areas de Momento A 2400 KgF 2 + 2 J ㅓ 6 73000155/80 B m Hormigón f·c = 280 kgf/cm E = 15000√√ Seccion de Viga Determinar las reacciones, Metodo Doble Integracion. 2000 KgF c 1800 g/m m + z z 6 Determinar las Reacciones en la viga. Nebdo Areas de Momento. 1500 kgf-m -2500 kg/m 2 c 8 306m 15 60cm
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Problem 1.
Determine the maximum deformation at point c. and use the Moment Areas Method.
Problem 2
Determine the reactions and use the Double Integration Method.
Problem 3
Determine the Reactions in the beam and use the Moment Area Method

Transcribed Image Text:Determinar la de Formacion Maxima en el punto c. Metodo Areas de Momento
A
2400 KgF
2
+
2
J
ㅓ
6
73000155/80
B
m
Hormigón f·c = 280 kgf/cm
E = 15000√√
Seccion de Viga
Determinar las reacciones, Metodo Doble Integracion.
2000 KgF
c
1800 g/m
m
+
z
z
6
Determinar las Reacciones en la viga. Nebdo Areas de Momento.
1500 kgf-m
-2500 kg/m
2
c
8
306m
15
60cm
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