**Problem Statement:**Determine the [OH⁻] concentration in 0.191 M M(OH)₂ solution, where M is a metal and M(OH)₂ is a soluble compound.**Explanation:**This problem requires us to calculate the concentration of hydroxide ions [OH⁻] in a given solution of a soluble metal hydroxide M(OH)₂. This type of question is helpful for understanding concepts related to chemical equilibrium, solubility, and stoichiometry.For a soluble metal hydroxide like M(OH)₂, which dissolves completely in water, the dissociation can be represented as follows:\[ \text{M(OH)}_2 \rightarrow \text{M}^{2+} + 2\text{OH}^- \]Given that the initial concentration of M(OH)₂ is 0.191 M, we can use the stoichiometry of the dissociation reaction to determine that the concentration of hydroxide ions [OH⁻] will be twice the concentration of M(OH)₂, because each formula unit produces two OH⁻ ions upon dissociation.Thus, the [OH⁻] concentration will be:\[ [OH^-] = 2 \times 0.191 \text{ M} \]\[ [OH^-] = 0.382 \text{ M} \]Therefore, the hydroxide ion concentration [OH⁻] in the 0.191 M M(OH)₂ solution is 0.382 M.

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Answered: Determin the cOH] concentration in o191…

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Chemistry

Determin the cOH] concentration in o191 M MIOH)z soluhon, wher M is a compound. metal and M(O H)z is a soluble

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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