Design the pin ended steel column in S275 steel to withstand an axial compressive load of 2500 KN over an unsupported height of 6.0 m assuming 356 x 368 x 129 UC. Design data : B=368.3 mm, d=290.2 mm, T=17.5 mm, t=10.7 mm, rx=15.6 cm, ry=9.39 mm, A=165 c

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A: Consider the given data. The column is fixed at both ends, KL=0.5×10000=5000 mm

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Q: A 1016 mm P 25 mm 330 mm 25 mm 254 mm A 12.5 mm

A: Lets Draw SFD and BMD in terms of P value   M=-P×1.016 kNmV=P kN

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Q: AW18 x 40 standard steel shape is used to support the loads shown on the beam. Assume P = 23 kips, w…

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Q: steel tube. Total axial deformation is 1 hat is the compressive load, P? Assume: uter dia. =1" nner…

A: Given data :Length of member (L)=20inAxial deformation = 0.5inModulus of elasticity of the steel is…

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A: Given data:Section properties-

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Q: A column is constructed using a circular steel tube filled with concrete. The properties are listed…

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Q: 160 kN LLET --3m-> -6m 400 kN 6m X 40 mm 200 mm 100 mm 20 mm

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A: Length of the solid bar= 6m Dia of Aluminium = 140mm Diameter for aluminum = 120mm

Q: Problem 2-4. For the following section, constructed of steel, determine: a) Moment at first yield…

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Q: ed at the two vertical supports only. a) What is the allowable bending stress in the beam in MPa? b)…

A: Given:-  W18X 97 steel beam  A-36 steel (Fy = 250 MPa). A. If the beam is laterally su A=18387 mm2…

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A: A composite beam cross-section-To Find-The axial stress in the steel portion.

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Q: A torque T-43 kip-in. is applied at end A of the composite shaft shown. Know that the modulus of…

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Q: Question 1 A composite beam cross section is made up of two rectangular strips. Each of (100x50) mm…

A: Given Data Es = 2 × 105 MPa  EBr = 1 × 105 MPa P = 15000 N  Determine the axial stress in steel…

Q: AW18 x 40 standard steel shape is used to support the loads shown on the beam. Assume P = 20 kips, w…

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Q: NE THE FORCE (Ib) E DATA BELOW:

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Q: The A992 structural steel bar and a 2014-T6 aluminium bar shown below are secured to rigid supports…

A: Given :

Q: AW18 x 40 standard steel shape is used to support the loads shown on the beam. Assume P = 29 kips, w…

A: Answer  We know that the Maximum bending stress is given by σmax = MmaxI*ymax Mmax = Maximum Moment…

Q: AW18 x 40 standard steel shape is used to support the loads shown on the beam. Assume P = 28 kips, w…

A: The beam with loadings is shown below.For W18 x 40,Depth h = 17.9 inMoment of Inertia, I = 612 in4

Q: The following steel circular bar (Es = 200 GPa) is divided into two segments. Segment 1 is tubular…

A: X = 6.0914mExplanation:Step 1: Step 2:

Q: AW18 × 40 standard steel shape is used to support the loads shown on the beam. Assume P = 20 kips, w…

A: Given Data: Load=p=20 kips w=5.8 kips LAB=4.0 ft LBC=4.0 ft LCD=13 ft

Q: The three suspender bars AD, BE, and CF are made of the same material (E = 70 GPa) and have equal…

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Q: The round bar shown in the figure has steel, brass and aluminum sections. Axial loads are applied at…

A: Draw the FBD of each section such that each part is in equilibrium. Then using the definition of…

Q: For the simply supported beam shown, a composite T-shaped section is to be used, shown below. Take…

A: The major stresses induced due to bending are normal stresses of tension and compression.

Q: B Steel E = 29 x 10 psi 7 = 490 lb* in. 4ft D Aluminura E = 10.1 x 10 psi 7 = 170 ³ Determine (a)…

A: For steel strut: E=29×106  psiγ=490 lb/ft3L=4 ft 12 in1 ft=4×12 ind=12 in=0.5 in For aluminium…

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Q: Fig3 6c.n ㅍ 25 3 um Tom 7 5cm Icm I 1cm

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Q: Question 1 A composite beam cross section is made up of two rectangular strips. Each of (100x50) mm…

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Q: The member shown A572 Grade SU Length of Properties: Pn = 330kn cb=1.06 Mn = 515 column is kn.m is…

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Q: nd the required base plate thickness (mm

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Q: a. The Euler stress Fe. b. The buckling stress Fcr c. The design strength d. The allowable strength…

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