Design the following items for an aerated grit chamber for the treatment of municipal wastewater. Using two grit chambers. The required data for design is listed in table below. The average flow rate Peaking factor The average detention time at peak flowrate The width: depth ratio Depth Air supply per unit of length Grit quantity per day at peak flow 0.45 m3/s 3 3 min 1.25: 1.0 3.0 m 0.5 m³/m. min 0.05 m³/10³ m³

Design the following items for an aerated grit chamber for the treatment of municipal wastewater. Using two grit chambers. The required data for design is listed in table below. The average flow rate Peaking factor The average detention time at peak flowrate The width: depth ratio Depth Air supply per unit of length Grit quantity per day at peak flow 0.45 m3/s 3 3 min 1.25: 1.0 3.0 m 0.5 m³/m. min 0.05 m³/10³ m³

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

What is the reason for the difference in theoretical and practical values in laboratory results for drainage through the holes?
A liquid limit test was performed on a soil sample It was found out that the moisture content at 14 blows was 72%, and that at 39 blows was 31%. What will be the resulting liquid limit of the soil? Round off to two decimal places. A Moving to another question will save this response. Activats Ruestion 5 of 20 Go to Settings to activate Winde ASUS CO CIB Ro D G 34
A constant velocity grit chamber is used in a small coastal community as a form of pre- treatment to incoming wastewater flows. The town regularly experiences a number of visitors during school holiday periods. If the usual wastewater flow is 10 ML per day, and the usual holiday period flow is 18 ML per day, design an appropriately sized grit chamber arrangement if the target grit has a diameter of 0.16 mm with a specific gravity of 2.75. Show your solutions for the following (but not necessarily in this order): 1. Determine the settling velocity for the target particle 2. Assuming a horizontal flow velocity of 0.32 m/s determine an appropriate overflow rate for the grit chamber 3. Determine an appropriate chamber length and cross sectional area and draw figures 4. Comment on how you could accommodate for the seasonal fluctuations in flows.
18. The results for sieve analysis is shown in the following table: Sieve No. 10 20 40 60 100 % Passing 69.3 59.1 48.3 38.5 28.4 19.8 4.5 Liquid Limit Plastic Limit Non-Plastic (NP) Non-Plastic (NP)
6. After your flash mix the water was sent to a clarification basin that was 24 feet in diameter and 20 feet tall. What was the detention time in hours of 0.43 MGD? 5.4 hours 4.3 hours 3.8 hours 2.3 hours After the water leaves your sedimentation basin, it is ready for filtration. Your two filters measure 10 feet in diameter. What is the filtration rate is gpm for your flow of 0.43 MGD? 19 gpm/sq/ft 29 gpm/sq/ft 39 gpm/sq/ft 49 gpm/sq/ft You have had a filtration breakthrough (failure) and have brought your old roughing filtration system on line. The old filter is 8 feet square and 4 feet deep. What is the filtration rate in gpm/sq/ft for your flow of 0.43 MGD? 10.33 gpm/sq/ft 8.55 gpm/sq/ft 5.99 gpm/sq/ft 4.66 gpm/sq/ft
NaOCI concentration in slip stream, Css = () lb/ft³? (*No unit) Qin = 8000 GPM Cin = 2.0 mg/L Slip Stream Qss = 2.3 L/s Css = ? Ib/ft3 Main service line Qout = 8000 GPM Cout = 4.0 mg/L %3D
What diameter would a circular clarifier have to be to remove 50 μm particles with 75% efficiency from a 4 MGD (million gallon per day) flow? Assume the particle specific gravity is 1.5 and the temperature is 10°C. Answer: 18 m
I) Two aggregates (Al and A2) were obtained from the field. A sieve analysis was performed on each sample, and the samples (originally 500g in mass) were brought to the oven dry condition (OD) and weighed. Data was obtained for each of the aggregates and is presented in the tables below. (Density of water-1g/cm) Table 1. Results from sieve analysis. Sieve Size Opening (mm) Weight of Aggregate retained (g) A1 A2 3/8" 9.5 No. 4 4.75 65 No. 8 2.36 60 25 No. 16 1.18 100 396 No. 30 0.6 50 No. 50 0.3 118.5 10 No. 100 0.15 75 15 Pan 75 Table 2. Absorption capacity and moisture content data. Al A2 500 g 500 g Field Weight Oven Dry Weight Absorption Capacity (%) 0.7 % 498.5 g 496 g 0.6 % a) Plot the grading curve for each aggregate (x-axis: sieve opening, y-axis: %passing). (Note: In the grading curves, you must show all data points. You can draw the gradation chart using excel or by hand. If you draw by hand, you have to use a ruler. The format of the gradation chart should be same as in the…
A rectangular sedimentation tank following coagulation- Exa flocculation is to treat a flow of 3000 m³ / day with a detention time of 6 hours. It is to be hand cleaned of sludge at 6 week intervals. The suspended solids concentration of the water is reduced from 250 mg/L to 5 mg|L by coagulation- flocculation. The settled sludge includes 40 mg/L (based on water flow) of metallic precipitate and has a moisture content of 85% and specific gravity of 1.24. Determine the volume of sludge produced between cleanings and the basic dimensions of the tank if the water depth just before cleaning is 3 m and its length is twice its width.
Q2. Using the sieve results of a batch of sand and gravel shown in the table below and if the P sand is 38 % and P Gravel is 62 %. answer the below questions: Amount Amount Sieve No. Retainded (g) Retainded (g) (Sand) (Gravel) 1.5" 20 1" 32 0.75" 17 169 0.5" 51 141 3/8" 119 118 No. 4 104 16 No. 8 44 14 No. 16 15
20 Choose the amount of cement in -2 tons and fine aggregate (sand) in cubic meters needed to pour one kilometer of a road 10 meters wide and 0.2 meters thick, knowing that the mixing ratio is 1:2:4 and the .density of cement is 1400 kg/m3 .3 1705.7 852.8 597 ) O O O O clear selection 425 Amount of fine O O aggregate in cubic meters Amount of cement in tons
Design a sedimentation basin for a water treatment plant with the following specifications assuming it is required to supply a city with a population of 50,000 people: Rectangular or square basin • Depth: 7-18 ft ● . • Width: 10-50 ft Detention time: 4-8 hours Flow through velocity: <0.55 ft/min Overflow rate: 400-1,100 gal/day-ft² Draw a figure to show calculated dimensions. You may consider to use SI units in calculations. ● ● Hint: Overflow rate is Flow/Surface Area; Detention time is Volume of tank/Flow rate; and Depth= Volume/Surface area