Design an integrator as shown in figure 2 to be operated with an AC signal of 5 kHz and to give a closed loop voltage gain of Af = 10 at w=1 rad/s.
Design an integrator as shown in figure 2 to be operated with an AC signal of 5 kHz and to give a closed loop voltage gain of Af = 10 at w=1 rad/s.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Solve Figure 2, 3, and 4. Please do it step by step without jumping any mathematical steps -for example, if you have to factor out dont just write the result of the factorization, but show the process-. And explain what is heppening in relevant steps. Thank you.
![**Educational Explanation of Two Amplifier Circuits**
**Figure 1: Difference Amplifier**
The difference amplifier in Figure 1 is characterized by the following values:
- Open-loop gain \( A_0 = 5 \times 10^5 \)
- Resistors:
- \( R_1 = 5 \, \text{k}\Omega \)
- \( R_F = 50 \, \text{k}\Omega \)
- \( R_a = 2 \, \text{k}\Omega \)
- \( R_x = 20 \, \text{k}\Omega \)
The input voltages are:
- \( v_b = 5 \, \text{mV} \)
- \( v_a = -15 \, \text{mV} \)
The task is to find the output voltage \( v_o \).
The diagram shows an operational amplifier (op-amp) used in a difference amplifier configuration. It processes two input voltages and amplifies the difference between these inputs. The circuit includes feedback and input resistors to define its gain and input impedance.
**Figure 2: Integrator Design**
Figure 2 illustrates a design for an integrator circuit. This design is intended to be operated with:
- An AC signal of 5 kHz
- A closed-loop voltage gain \( A_f = 10 \) at \( \omega = 1 \, \text{rad/s} \)
The components involved are:
- Resistors: \( R_1 \) and \( R_F \)
- Capacitor: \( C_F \)
- Power supply voltages: \( +V_{CC} \) and \( -V_{EE} \)
This circuit setup uses an op-amp with a feedback capacitor to integrate the input signal over time, providing an output proportional to the integral of the input voltage. The resistor \( R_x \) is set as the parallel combination of \( R_1 \) and \( R_F \).
The diagrams contain multiple circuit notations including:
- Inverting and non-inverting inputs (\(+\) and \(-\) terminals)
- Feedback paths
- Input and output points marked with voltages (\(v_i, v_o\))
This explanation aims to provide insight into the workings of amplifier and integrator circuits through practical configurations and component specifications.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9d93d5b-3633-421c-9998-1d7367e4399c%2F6adcc958-2628-4e5e-bce4-36a807b60a82%2Fqyzt09g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Explanation of Two Amplifier Circuits**
**Figure 1: Difference Amplifier**
The difference amplifier in Figure 1 is characterized by the following values:
- Open-loop gain \( A_0 = 5 \times 10^5 \)
- Resistors:
- \( R_1 = 5 \, \text{k}\Omega \)
- \( R_F = 50 \, \text{k}\Omega \)
- \( R_a = 2 \, \text{k}\Omega \)
- \( R_x = 20 \, \text{k}\Omega \)
The input voltages are:
- \( v_b = 5 \, \text{mV} \)
- \( v_a = -15 \, \text{mV} \)
The task is to find the output voltage \( v_o \).
The diagram shows an operational amplifier (op-amp) used in a difference amplifier configuration. It processes two input voltages and amplifies the difference between these inputs. The circuit includes feedback and input resistors to define its gain and input impedance.
**Figure 2: Integrator Design**
Figure 2 illustrates a design for an integrator circuit. This design is intended to be operated with:
- An AC signal of 5 kHz
- A closed-loop voltage gain \( A_f = 10 \) at \( \omega = 1 \, \text{rad/s} \)
The components involved are:
- Resistors: \( R_1 \) and \( R_F \)
- Capacitor: \( C_F \)
- Power supply voltages: \( +V_{CC} \) and \( -V_{EE} \)
This circuit setup uses an op-amp with a feedback capacitor to integrate the input signal over time, providing an output proportional to the integral of the input voltage. The resistor \( R_x \) is set as the parallel combination of \( R_1 \) and \( R_F \).
The diagrams contain multiple circuit notations including:
- Inverting and non-inverting inputs (\(+\) and \(-\) terminals)
- Feedback paths
- Input and output points marked with voltages (\(v_i, v_o\))
This explanation aims to provide insight into the workings of amplifier and integrator circuits through practical configurations and component specifications.
![**Design a Differentiator Circuit**
**Objective:** Design a differentiator circuit as shown in **Figure 3** to achieve \( f_L = 5 \text{kHz} \) and \( f_H = 10 \text{kHz} \). The pass band gain is \(|A_{PB}| = 20\). Use PSpice/Multisim to verify your answer. Upload a snapshot of the PSpice/Multisim output.
**Figure 3: Differentiator Circuit Diagram**
- **Components and Notations:**
- \( C_1 \): Capacitor
- \( R_1, R_F \): Resistors
- \( R_x = R_F \): Feedback resistor
- \( A = \infty \): Operational amplifier with infinite open-loop gain
- \( v_s \): Input voltage
- \( v_o \): Output voltage
**Two Inverting Op-Amps Cascaded**
**Objective:** Explore the circuit shown in **Figure 4**, consisting of two cascaded inverting op-amps. The unity-gain bandwidth of the op-amps is \( f_u = 1 \text{MHz} \), and the slew rate is \( SR = 6 \text{V/ms} \).
1. **Analysis:**
a. Given:
- \( R_1 = 20 \text{k}\Omega \)
- \( R_2 = 100 \text{k}\Omega \)
- \( R_3 = 150 \text{k}\Omega \)
- \( R_4 = 520 \text{k}\Omega \)
- \( R_5 = 160 \text{k}\Omega \)
Determine the voltage gain \( A_f = \frac{v_o}{v_1} \).
2. **Verification:**
b. Use PSpice/Multisim to verify your results. Upload a snapshot of the PSpice/Multisim output.
**Figure 4: Cascaded Inverting Op-Amps Diagram**
- **Components and Notations:**
- \( R_1, R_2, R_3, R_4, R_5 \): Resistors
- \( v_1 \): Input voltage
- \( v_{o1} \): Intermediate voltage output of the first op-amp
- \( v_o \): Final output](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9d93d5b-3633-421c-9998-1d7367e4399c%2F6adcc958-2628-4e5e-bce4-36a807b60a82%2Ftnapw54_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Design a Differentiator Circuit**
**Objective:** Design a differentiator circuit as shown in **Figure 3** to achieve \( f_L = 5 \text{kHz} \) and \( f_H = 10 \text{kHz} \). The pass band gain is \(|A_{PB}| = 20\). Use PSpice/Multisim to verify your answer. Upload a snapshot of the PSpice/Multisim output.
**Figure 3: Differentiator Circuit Diagram**
- **Components and Notations:**
- \( C_1 \): Capacitor
- \( R_1, R_F \): Resistors
- \( R_x = R_F \): Feedback resistor
- \( A = \infty \): Operational amplifier with infinite open-loop gain
- \( v_s \): Input voltage
- \( v_o \): Output voltage
**Two Inverting Op-Amps Cascaded**
**Objective:** Explore the circuit shown in **Figure 4**, consisting of two cascaded inverting op-amps. The unity-gain bandwidth of the op-amps is \( f_u = 1 \text{MHz} \), and the slew rate is \( SR = 6 \text{V/ms} \).
1. **Analysis:**
a. Given:
- \( R_1 = 20 \text{k}\Omega \)
- \( R_2 = 100 \text{k}\Omega \)
- \( R_3 = 150 \text{k}\Omega \)
- \( R_4 = 520 \text{k}\Omega \)
- \( R_5 = 160 \text{k}\Omega \)
Determine the voltage gain \( A_f = \frac{v_o}{v_1} \).
2. **Verification:**
b. Use PSpice/Multisim to verify your results. Upload a snapshot of the PSpice/Multisim output.
**Figure 4: Cascaded Inverting Op-Amps Diagram**
- **Components and Notations:**
- \( R_1, R_2, R_3, R_4, R_5 \): Resistors
- \( v_1 \): Input voltage
- \( v_{o1} \): Intermediate voltage output of the first op-amp
- \( v_o \): Final output
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