Design a trapezoidal open channel of most efficient section with one side slope (V:H) and the other at 3:4 (V:H) to carry 5 cubic meters of water through a slope o per kilometer. Use Manning's Equation with n = 0.025. Given: Q = 5 m/s n = 0.025 X1 b X2 freeboard Vws 2 V13 5/3 3. Y, Y2

Q: You must determine the depth of the water over the obstacle presented in figure 4 considering that…

A: ###Depth of water over the obstacle placed in channel flow####

Q: O A rectangular channel 1.30 wide carries 1.10 m/s of water at a depth of 0.85 m. If a 30-cm wide…

A: Equating specific energy of channel at both section to get elevation of water surface

Q: Water is flowing uniformly in an open channel (triangular shap has a 1:2 (v:h) side slope and a…

A:

Q: Water flows in a 1.5-m wide rectangular channel with a constant bed slope So = 0.144 (see figure…

A:

Q: The bed of a corrugated channel, with Manning’s coeffcient n =0.019 s/m^1/3 drops 25 m every 1500 m.…

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Q: A rectangular channel is 6.3 m wide and has depth of flow of 1.7m. The slope of the channel bed is…

A: Given- Width of rectangular channel (b) =6.3 m depth of flow (d) = 1.7m. The slope of the channel…

Q: Design a semi-circular open channel (n=0.014) that is anticipated to convey 10cumecs of water. The…

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Q: The water velocity in the channel shown in the figure has a velocity distribution across the…

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Highway Drainage

Highway drainage is the process of extracting and regulating the excess surface water on the pavement by giving the desired slope. The construction of a highway drain helps to divert the water present on the surface, and sub-grade by the means of slope. Highway drainage systems are a necessary part of smooth functioning of traffic, since the highway drainage systems provide proper disposal of unwanted substances from the highways.