Design a program using the 8085 microprocessor assembly language that performs the following tasks: 1. Initialize register A with a value of OxFF. 2. Load a 16-bit value from memory location 2000H into register pair HL. 3. Subtract the value in register B from the value in register A. 4. Store the result in memory location 3000H. 5. If the result is negative, jump to memory location 4000H.
Design a program using the 8085 microprocessor assembly language that performs the following tasks: 1. Initialize register A with a value of OxFF. 2. Load a 16-bit value from memory location 2000H into register pair HL. 3. Subtract the value in register B from the value in register A. 4. Store the result in memory location 3000H. 5. If the result is negative, jump to memory location 4000H.
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![### 8085 Microprocessor Assembly Language Programming
The 8085 microprocessor assembly language is a low-level programming language used to program the 8085 microprocessor. Below is a step-by-step guide to designing a program that performs specific tasks using the 8085 assembly language.
#### Program Tasks:
1. **Initialize register A with a value of 0xFF.**
2. **Load a 16-bit value from memory location 2000H into register pair HL.**
3. **Subtract the value in register B from the value in register A.**
4. **Store the result in memory location 3000H.**
5. **If the result is negative, jump to memory location 4000H.**
### Steps Explained:
1. **Initialize Register A:**
- The first step is to initialize the accumulator (register A) with the hexadecimal value 0xFF.
```assembly
MVI A, 0xFF ; Move immediate value 0xFF into register A
```
2. **Load 16-bit Value into HL Register Pair:**
- Load the 16-bit value from memory location 2000H into the HL register pair.
```assembly
LHLD 2000H ; Load the contents of memory location 2000H into HL register pair
```
3. **Subtract Value in B from A:**
- Subtract the value in register B from the value in register A.
```assembly
SUB B ; Subtract the contents of B from A
```
4. **Store the Result in Memory:**
- Store the result of the subtraction operation in memory location 3000H.
```assembly
STA 3000H ; Store the contents of A into memory location 3000H
```
5. **Conditional Jump if Result is Negative:**
- Check if the result of the subtraction is negative and if true, jump to memory location 4000H.
```assembly
JM 4000H ; Jump to 4000H if the result is negative
```
### Complete Program:
```assembly
MVI A, 0xFF ; Initialize register A with 0xFF
LHLD 2000H ; Load 16-bit value from memory location 2000H into HL pair
SUB B ; Sub](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec969527-ef6f-4c91-8f92-7779f95f1ab5%2Fb00e6c1a-c2f0-4123-a78f-ae3aa2e83cc3%2F0cbwy9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### 8085 Microprocessor Assembly Language Programming
The 8085 microprocessor assembly language is a low-level programming language used to program the 8085 microprocessor. Below is a step-by-step guide to designing a program that performs specific tasks using the 8085 assembly language.
#### Program Tasks:
1. **Initialize register A with a value of 0xFF.**
2. **Load a 16-bit value from memory location 2000H into register pair HL.**
3. **Subtract the value in register B from the value in register A.**
4. **Store the result in memory location 3000H.**
5. **If the result is negative, jump to memory location 4000H.**
### Steps Explained:
1. **Initialize Register A:**
- The first step is to initialize the accumulator (register A) with the hexadecimal value 0xFF.
```assembly
MVI A, 0xFF ; Move immediate value 0xFF into register A
```
2. **Load 16-bit Value into HL Register Pair:**
- Load the 16-bit value from memory location 2000H into the HL register pair.
```assembly
LHLD 2000H ; Load the contents of memory location 2000H into HL register pair
```
3. **Subtract Value in B from A:**
- Subtract the value in register B from the value in register A.
```assembly
SUB B ; Subtract the contents of B from A
```
4. **Store the Result in Memory:**
- Store the result of the subtraction operation in memory location 3000H.
```assembly
STA 3000H ; Store the contents of A into memory location 3000H
```
5. **Conditional Jump if Result is Negative:**
- Check if the result of the subtraction is negative and if true, jump to memory location 4000H.
```assembly
JM 4000H ; Jump to 4000H if the result is negative
```
### Complete Program:
```assembly
MVI A, 0xFF ; Initialize register A with 0xFF
LHLD 2000H ; Load 16-bit value from memory location 2000H into HL pair
SUB B ; Sub
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