### 8085 Microprocessor Assembly Language ProgrammingThe 8085 microprocessor assembly language is a low-level programming language used to program the 8085 microprocessor. Below is a step-by-step guide to designing a program that performs specific tasks using the 8085 assembly language.#### Program Tasks:1. **Initialize register A with a value of 0xFF.**2. **Load a 16-bit value from memory location 2000H into register pair HL.**3. **Subtract the value in register B from the value in register A.**4. **Store the result in memory location 3000H.**5. **If the result is negative, jump to memory location 4000H.**### Steps Explained:1. **Initialize Register A:** - The first step is to initialize the accumulator (register A) with the hexadecimal value 0xFF. ```assembly MVI A, 0xFF ; Move immediate value 0xFF into register A ```2. **Load 16-bit Value into HL Register Pair:** - Load the 16-bit value from memory location 2000H into the HL register pair. ```assembly LHLD 2000H ; Load the contents of memory location 2000H into HL register pair ```3. **Subtract Value in B from A:** - Subtract the value in register B from the value in register A. ```assembly SUB B ; Subtract the contents of B from A ```4. **Store the Result in Memory:** - Store the result of the subtraction operation in memory location 3000H. ```assembly STA 3000H ; Store the contents of A into memory location 3000H ```5. **Conditional Jump if Result is Negative:** - Check if the result of the subtraction is negative and if true, jump to memory location 4000H. ```assembly JM 4000H ; Jump to 4000H if the result is negative ```### Complete Program:```assemblyMVI A, 0xFF ; Initialize register A with 0xFFLHLD 2000H ; Load 16-bit value from memory location 2000H into HL pairSUB B ; Sub

Design a program using the 8085 microprocessor assembly language that performs the following tasks: 1. Initialize register A with a value of OxFF. 2. Load a 16-bit value from memory location 2000H into register pair HL. 3. Subtract the value in register B from the value in register A. 4. Store the result in memory location 3000H. 5. If the result is negative, jump to memory location 4000H.

Design a program using the 8085 microprocessor assembly language that performs the following tasks: 1. Initialize register A with a value of OxFF. 2. Load a 16-bit value from memory location 2000H into register pair HL. 3. Subtract the value in register B from the value in register A. 4. Store the result in memory location 3000H. 5. If the result is negative, jump to memory location 4000H.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

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Question

### 8085 Microprocessor Assembly Language Programming

The 8085 microprocessor assembly language is a low-level programming language used to program the 8085 microprocessor. Below is a step-by-step guide to designing a program that performs specific tasks using the 8085 assembly language.

#### Program Tasks:

1. **Initialize register A with a value of 0xFF.**
2. **Load a 16-bit value from memory location 2000H into register pair HL.**
3. **Subtract the value in register B from the value in register A.**
4. **Store the result in memory location 3000H.**
5. **If the result is negative, jump to memory location 4000H.**

### Steps Explained:

1. **Initialize Register A:**
- The first step is to initialize the accumulator (register A) with the hexadecimal value 0xFF.
```assembly
MVI A, 0xFF ; Move immediate value 0xFF into register A
```

2. **Load 16-bit Value into HL Register Pair:**
- Load the 16-bit value from memory location 2000H into the HL register pair.
```assembly
LHLD 2000H ; Load the contents of memory location 2000H into HL register pair
```

3. **Subtract Value in B from A:**
- Subtract the value in register B from the value in register A.
```assembly
SUB B ; Subtract the contents of B from A
```

4. **Store the Result in Memory:**
- Store the result of the subtraction operation in memory location 3000H.
```assembly
STA 3000H ; Store the contents of A into memory location 3000H
```

5. **Conditional Jump if Result is Negative:**
- Check if the result of the subtraction is negative and if true, jump to memory location 4000H.
```assembly
JM 4000H ; Jump to 4000H if the result is negative
```

### Complete Program:
```assembly
MVI A, 0xFF ; Initialize register A with 0xFF
LHLD 2000H ; Load 16-bit value from memory location 2000H into HL pair
SUB B ; Sub

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