Design a digital combinational logic circuit with four inputs: a, b, c & d, where (a, b) represents one 2-bit unsigned binary number A{1:0]; and (c, d) represents another 2-bit unsigned binary number B[1:0] (i.e. both A and B are in the range 0 to 3). The circuit has 4 outputs (or you can regard it as being 4 distinct circuits, each with a single bit output) – in other words, the truth table will have 4 input columns and 4 output columns. These output columns together repesent the 4-bit product Y[3:0] Y = A* B For instance, inputs corresponding to "3 , 2" would output bits corresponding to 6 - Start by drawing up the truth table any of the poutput columns) Make sure you label your input and output columns correctly - everything else depends on getting the table right! then derive the algebraic expression for the third bit of the output, Y[2] - and simplify it - Finally, draw the resulting circuit (show only those rows which produce a 1 in -

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Design a digital combinational logic circuit with four inputs: a, b, c & d, where (a, b)
represents one 2-bit unsigned binary number A{1:0]; and (c, d) represents another 2-bit
unsigned binary number B[1:0] (i.e. both A and B are in the range 0 to 3).
The circuit has 4 outputs (or you can regard it as being 4 distinct circuits, each with a single
bit output) – in other words, the truth table will have 4 input columns and 4 output columns.
These output columns together repesent the 4-bit product Y[3:0]
Y = A * B
For instance, inputs corresponding to "3 , 2" would output bits corresponding to 6
- Start by drawing up the truth table
any of the poutput columns)
Make sure you label your input and output columns correctly – everything else
depends on getting the table right!
- then derive the algebraic expression for the third bit of the output, Y[2]
- and simplify it
- Finally, draw the resulting circuit
(show only those rows which produce a 1 in
Transcribed Image Text:Design a digital combinational logic circuit with four inputs: a, b, c & d, where (a, b) represents one 2-bit unsigned binary number A{1:0]; and (c, d) represents another 2-bit unsigned binary number B[1:0] (i.e. both A and B are in the range 0 to 3). The circuit has 4 outputs (or you can regard it as being 4 distinct circuits, each with a single bit output) – in other words, the truth table will have 4 input columns and 4 output columns. These output columns together repesent the 4-bit product Y[3:0] Y = A * B For instance, inputs corresponding to "3 , 2" would output bits corresponding to 6 - Start by drawing up the truth table any of the poutput columns) Make sure you label your input and output columns correctly – everything else depends on getting the table right! - then derive the algebraic expression for the third bit of the output, Y[2] - and simplify it - Finally, draw the resulting circuit (show only those rows which produce a 1 in
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