Design a 2-bit multiplier with 2 2-bit inputs (X₁X and Y₁Y0) and gives out a 4-bit product (P3P2P₁P0) using ACT1 logic modules only, no other gates are allowed. Intermediate logic module signals (F1, F2, and S) are not accessible to other logic modules. A0 A1- SA- ВО B1- SB- SO S1 ACT 1 Logic Module is equivalent to AO A1 SA- ВО B1 SB SO SO SO S1 Logic Module 0 F1 1 0 1 F2 M3 0 1 4

Design a 2-bit multiplier with 2 2-bit inputs (X₁X and Y₁Y0) and gives out a 4-bit product (P3P2P₁P0) using ACT1 logic modules only, no other gates are allowed. Intermediate logic module signals (F1, F2, and S) are not accessible to other logic modules. A0 A1- SA- ВО B1- SB- SO S1 ACT 1 Logic Module is equivalent to AO A1 SA- ВО B1 SB SO SO SO S1 Logic Module 0 F1 1 0 1 F2 M3 0 1 4

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter22: Sequence Control

Section: Chapter Questions

Problem 6SQ: Draw a symbol for a solid-state logic element AND.

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Design a 2-bit multiplier with 2 2-bit inputs (X1X0 and Y1Y0) and gives out a 4-bit product (P3P2P1P0). Using ACT1 logic modules shown below only, no other gates are allowed. Intermediate logic module signals (F1, F2, and S) are not accessible to other logic modules.
Design a 2-bit multiplier with 2 2-bit inputs (X1X0 and Y1Y0) and gives out a 4-bit product (P3P2P1P0). Using ACT1 logic modules shown below only, no other gates are allowed. Intermediate logic module signals (F1, F2, and S) are not accessible to other logic modules.
Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).
USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…
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answere fast please question from DIGITAL LOGIC DESIGN TOPIC : Designing Combinational Logic You are designing a water level circuit using 74ALS151 (8 to 1 Multiplexer IC)* When input is 0000 that means tank is empty.* When input is 1111 that means tank is full.* When input is below 5, that means water level is low.* So, make a circuit using 74ALS151 Multiplexer IC that shows a "low water" indicator light(by setting an output L to 1) when the water level drops below level 5.
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Design a combinational circuit with 3-inputs and 1-output. The output is equal to logic-1 when the binary value of the input is less than 3. And the output is logic-0 otherwise.
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