Descriptives Statistic Std. Error Secondary Education, General Pupils - Austria Mean 462518.8158 3644.08262 95% Confidence Interval Lower Bound 455076.6062 for Mean Upper Bound 469961.0253 5% Trimmed Mean 462628.2684 Median 460934.0000 Variance 411659481.3 Std. Deviation 20289.39332 Minimum 427286.00 Maximum 497517.00 Range 70231.00 Interquartile Range 36415.08 Skewness -.126 .421 Kurtosis -1.274 .821 Secondary Education, General Pupils - United Kingdom Mean 4272214.141 45166.75145 95% Confidence Interval Lower Bound 4179971.329 for Mean Upper Bound 4364456.954 5% Trimmed Mean 4267656.066 Median 4317382.000 Variance 63241098532 Std. Deviation 251477.8291 Minimum 3.83E+006 Maximum 4.81E+006 Range 972310.00 Interquartile Range Skewness 336620.00 .109 421 Kurtosis -.449 .821 Tests of Normality Kolmogorov-Smirnov" Sig. Shapiro-Wilk Statistic df Statistic df Sig. Secondary Education, General Pupils - Austria .138 31 .137 .942 31 .093 Secondary Education, General Pupils - United Kingdom .087 31 .200 .978 31 .753 *. This is a lower bound of the true significance. a. Lilliefors Significance Correction

Q: what is the horizontal change on a graph described as ?

A: According to the given information it is required to describe horizontal change on a graph.

Q: what would the interpret for the solution for the graphed systerm?

A: The point at which the lines intersect is the intersection point.

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A: Answer is Yes.

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A: The given equation is y=x2x2+147 to find the x intercept put y=0 y=x2x2+1470=x2x2+147x2=0x=0…

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Q: How would I graph this segment

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A: Here we use the concept of the linear equations.

Q: Can you please provide a graph

A: We can draw the graph .

Q: please help me gragh

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Q: can you explain how you plotted the points?

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A: The transformation rule of the graph function

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A: Given:

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A: Step 1: