Good evening, i am working on this arrays problem and was hoping you could help with it please? (my programming language is c++)Thanks! **Array Manipulation Instructions**1. **Use Provided Values:** - Ensure that you use the values from the given array.2. **Print Original Array:** - Output the original array to the console for reference.3. **Modify Odd Values:** - Identify odd numbers in the array. - Replace each odd number with an even number.4. **Display Updated Array:** - Print the modified array to the console to show changes. **Assignment Description:**For this assignment, you will write a program that removes the odd numbers from an array and replaces them with even numbers. Your array must have 10 elements and be initialized with the following numbers: 42, 9, 23, 101, 99, 22, 13, 5, 77, 28.

ALGORITHMS: START Take the given value.int arr[10]={42,9,23,101,99,22,13,5,77,28};cout<<"The original array is: "; //Use for loopfor(i=0;i<=9;i++)cout<<arr[i]<<" "; //Print even numbercout<<"\n\nYour even number array is: ";for(i=0;i<=9;i++) //If the value is oddif(arr[i]%2!=0)arr[i]=arr[i]*2;cout<<arr[i]<<" "; elsecout<<arr[i]<<" ";return 0; ENDCode: C++ #include<iostream>using namespace std; int main(){int i;int arr[10]={42,9,23,101,99,22,13,5,77,28};cout<<"The original array is: ";for(i=0;i<=9;i++){cout<<arr[i]<<" ";}cout<<"\n\nYour even number array is: ";for(i=0;i<=9;i++){if(arr[i]%2!=0){arr[i]=arr[i]*2;cout<<arr[i]<<" ";}else{cout<<arr[i]<<" ";}}return 0;}Output: