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Describe the graph of the equation. r = -6i+ (1 – 1? )j + t k O It is a parabola in the plane z = -6, with vertex at (1, 0, -6), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 0, 1), opening to the 'right' (positive y) O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'right' (positive y) O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening up (positive z).

Describe the graph of the equation. r = -6i+ (1 – 1? )j + t k O It is a parabola in the plane z = -6, with vertex at (1, 0, -6), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 0, 1), opening to the 'right' (positive y) O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'right' (positive y) O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening up (positive z).

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Describe the graph of the equation. r = -6i+ (1 – 1²)j + t k O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 0, 1), opening to the 'right' (positive y). O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'right' (positive y). O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening up (positive z).
Transcribed Image Text:Describe the graph of the equation. r = -6i+ (1 – 1²)j + t k O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 0, 1), opening to the 'right' (positive y). O It is a parabola in the plane z = -6, with vertex at (1, 0, – 6), opening to the 'right' (positive y). O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening to the 'left' (negative y). O It is a parabola in the plane x = -6, with vertex at (-6, 1, 0), opening up (positive z).
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