Describe the graph of the equation. r =-18i+(1-j+:k O Itisa parabola in the plane: = -18, with vertex at (1, 0, -15), opening to the left (negative y). O Itisa parabola in the planex= - 18, with vertexat (-18, 1, 0), opening up (positive:). O Itisa parabola in the planex= -18, with vertexat (-18, 1, 0), opening to the left (negative y). O tisa parabola in the planex = -18, with vertex at (-18, 0, 1), opening to the 'right' (positivey). O tisa parabola in the plane: = -18, with vertex at (1,0, -18), opening to the right' (positive y).

Q: Write an equation for a parabola with X intercepts (-3,0) and (5,0)which passes through the point (4…

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