Describe how you would (carefully!) prepare 25.00 mL of an aqueous calicheamicin gamma-1 solution that could kill 1.0×10^8 bacteria, starting from a 5.00×10−9M stock solution of the antibiotic. Complete the explanation.

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Describe how you would (carefully!) prepare 25.00 mL of an aqueous calicheamicin gamma-1 solution that could kill 1.0×10^8 bacteria, starting from a 5.00×10−9M stock solution of the antibiotic. Complete the explanation.
Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. Words may be used more than once.
 
The 25.00 mL of antibiotic solution needs to contain a minimum of ______
molecules of the drug. Calculate the_____ of drug this represents. The concentration of the stock solution is ______ Then, L stock solution = mol drug/M solution; L = mol/________M.
I Review | Constants | Periodic Table
Calicheamicin gamma-1, C55 H74IN3O21 S4, is one of the
most potent antibiotics known: One molecule kills one bacterial
cel.
Part A
Describe how you would (carefully!) prepare 25.00 mL of an aqueous calicheamicin gamma-1 solution that could kill 1.0 x 10° bacteria, starting from
a 5.00 x 10 "M stock solution of the antibiotic. Complete the explanation.
Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before
submitting your answer. Words may be used more than once.
Reset
Help
5.00 x 10-9
The 25.00 mL of antibiotic solution needs to
contain a minimum of 5.00 x 10 9
mass
molecules of the drug. Calculate the moles
1.0 x 108
of drug this represents. The concentration of
moles
the stock solution is volume
Then, L
volume
stock solution = mol drug/M solution;
L = mol/ 1.0 × 10 | M.
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 5 attempts remaining
You filled in 3 of 4 blanks incorrectly. Note that the introduction states that one molecule of antibiotic kills one bacterial cell. There are
1.0 x 10% bacterial cells. Use this to determine the number of molecules of antibiotic you need.
Transcribed Image Text:I Review | Constants | Periodic Table Calicheamicin gamma-1, C55 H74IN3O21 S4, is one of the most potent antibiotics known: One molecule kills one bacterial cel. Part A Describe how you would (carefully!) prepare 25.00 mL of an aqueous calicheamicin gamma-1 solution that could kill 1.0 x 10° bacteria, starting from a 5.00 x 10 "M stock solution of the antibiotic. Complete the explanation. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. Words may be used more than once. Reset Help 5.00 x 10-9 The 25.00 mL of antibiotic solution needs to contain a minimum of 5.00 x 10 9 mass molecules of the drug. Calculate the moles 1.0 x 108 of drug this represents. The concentration of moles the stock solution is volume Then, L volume stock solution = mol drug/M solution; L = mol/ 1.0 × 10 | M. Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining You filled in 3 of 4 blanks incorrectly. Note that the introduction states that one molecule of antibiotic kills one bacterial cell. There are 1.0 x 10% bacterial cells. Use this to determine the number of molecules of antibiotic you need.
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