Describe how to prepare 0.250 L of 0.600 M HCl solution, starting with a 2.00 M HCl solution. What volume (in L) of the 2.00 M solution will you need? Round your answer to 3 significant digits. L G d
Describe how to prepare 0.250 L of 0.600 M HCl solution, starting with a 2.00 M HCl solution. What volume (in L) of the 2.00 M solution will you need? Round your answer to 3 significant digits. L G d
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Preparation of Specific Solutions**
To prepare 0.250 L (liters) of a 0.600 M (molar) HCl solution from a 2.00 M HCl stock solution, follow these instructions. Calculate the required volume of the 2.00 M solution using the dilution formula:
\[ C_1 \times V_1 = C_2 \times V_2 \]
Where:
- \( C_1 \) is the concentration of the stock solution (2.00 M),
- \( V_1 \) is the volume of the stock solution needed,
- \( C_2 \) is the desired concentration (0.600 M),
- \( V_2 \) is the desired final volume (0.250 L).
Solve for \( V_1 \):
\[ V_1 = \frac{C_2 \times V_2}{C_1} \]
**Diagram Explanation**
The diagram includes a text box for inputting the calculated volume in liters. To solve and enter your result, calculate based on the formula above, ensuring accuracy to 3 significant digits.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc1b7a372-1344-4f7f-af15-7d7e9d0720e7%2Fbb6469e5-d254-4b53-9f01-0ea34bffe936%2Floogj8b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Preparation of Specific Solutions**
To prepare 0.250 L (liters) of a 0.600 M (molar) HCl solution from a 2.00 M HCl stock solution, follow these instructions. Calculate the required volume of the 2.00 M solution using the dilution formula:
\[ C_1 \times V_1 = C_2 \times V_2 \]
Where:
- \( C_1 \) is the concentration of the stock solution (2.00 M),
- \( V_1 \) is the volume of the stock solution needed,
- \( C_2 \) is the desired concentration (0.600 M),
- \( V_2 \) is the desired final volume (0.250 L).
Solve for \( V_1 \):
\[ V_1 = \frac{C_2 \times V_2}{C_1} \]
**Diagram Explanation**
The diagram includes a text box for inputting the calculated volume in liters. To solve and enter your result, calculate based on the formula above, ensuring accuracy to 3 significant digits.
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