Derive the stopping sight distance (SSD) formula as shown: where V t f G d₂ SSD = d₂ + d₂ vt 3.6 d₁ = 2g(3.6²) (f+G) is the running speed at perception of the object or obstruction (in k is the perception-reaction time (in s) is the coefficient of friction between the tires and pavement is the gradient (+ for uphill, - for downhill) Hint: Use the concept of conservation of energy (see Figure 1). Account for kinetic, potential, and friction energies. Recall: KE=mv², PE = mgh, and W₁ = fWd₂ (W is the weight of the vehicle) Hint 2: If 0-0, sin = tan 8. Vo = v 1 0 d₂ Figure V₁ = 0
Derive the stopping sight distance (SSD) formula as shown: where V t f G d₂ SSD = d₂ + d₂ vt 3.6 d₁ = 2g(3.6²) (f+G) is the running speed at perception of the object or obstruction (in k is the perception-reaction time (in s) is the coefficient of friction between the tires and pavement is the gradient (+ for uphill, - for downhill) Hint: Use the concept of conservation of energy (see Figure 1). Account for kinetic, potential, and friction energies. Recall: KE=mv², PE = mgh, and W₁ = fWd₂ (W is the weight of the vehicle) Hint 2: If 0-0, sin = tan 8. Vo = v 1 0 d₂ Figure V₁ = 0
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Derive the stopping sight distance (SSD) formula as shown:
where
Hint:
V
t
f
G
d₂
(W is the weight of the vehicle)
SSD = d₁ + d₂
vt
3.6
D²
Hint 2: If 00, sin 8 tan 8.
=
d₁ =
is the running speed at perception of the object or obstruction (in kph)
is the perception-reaction time (in s)
is the coefficient of friction between the tires and pavement
is the gradient (+ for uphill, - for downhill)
Use the concept of conservation of energy
(see Figure 1). Account for kinetic,
potential, and friction energies.
Recall: KE=mv², PE = mgh, and W, = fWd₂
2g (3.6²) (f ± G)
Vo = v
1 O
d₂
Figure 1
Vf=0
02
0, tan 8 = G
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