ANSWER MUST BE WRITTEN IN THE SAME FORM AS THE EXAMPLE. 12WN8{ int x;int z;910111213 }z = 3;{ int f(int x) {if x=0 then {z = 1 }{elsez = f(x-1) *2 };return z;};x = f (3);;3 [z-3, x=?]41150000000B5858569co on89co on8900 089[f={}, z=3, x=?]>>[x=3, f={}, z=3, x=?][x=2, x-3, f={}, z=3, x=?][x=1, x=2, x=3, f={}, z=3, x=?][x=0, x=1, x=2, x=3, f{}, z=3, x=?][x=0, x=1, x=2, x=3, f={}, z=1, x=?][res=1 x=0, x=1, x=2, x=3, f={}, z=1,[x=1, x=2, x=3, f={}, z=2, x=?][res=2, x=1, x=2, x=3, f={}, z=2, x=?][x=2, x=3, f={}, z=4, x=?][res-4, x-2, x=3, f={}, z=4, x=?][x=3, f={}, z=8, x=?][res-8, x-3, f={}, z-8, x=?]11 [f-{}, z-8, x-8]12 [z-8, x=8]13 [1 Consider the following block. Assume static scoping and call-by-value parameter passing.1 = {2WNH3L10111213};int x;int z;z :=4;{};int f(int x) {if x==0 then {z = 1 }else {z = f(x-1) *z+2 };return z;};x := f (3);Demonstrate the computations that take place during the evaluation of this block, that is, give asequence of lines each showing the complete runtime stack with all activation records after eachstatement or function call. For recursive calls use one stack onto which a new activation record ispushed on for each recursive function call.

Here's a step-by-step demonstration of the computations that take place during the evaluation of the…

Demonstrate the computations that take place during the evaluation of this block, that is, give a sequence of lines each showing the complete runtime stack with all activation records after each statement or function call. For recursive calls use one stack onto which a new activation record is pushed on for each recursive function call.

Demonstrate the computations that take place during the evaluation of this block, that is, give a sequence of lines each showing the complete runtime stack with all activation records after each statement or function call. For recursive calls use one stack onto which a new activation record is pushed on for each recursive function call.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

ANSWER MUST BE WRITTEN IN THE SAME FORM AS THE EXAMPLE.

1
2
WN
8
{ int x;
int z;
9
10
11
12
13 }
z = 3;
{ int f(int x) {
if x=0 then {
z = 1 }
{
else
z = f(x-1) *2 };
return z;
};
x = f (3);
;
3 [z-3, x=?]
4
11
5
0000000
B
5
8
5
8
5
6
9
co on
8
9
co on
8
9
00 0
8
9
[f={}, z=3, x=?]
>>
[x=3, f={}, z=3, x=?]
[x=2, x-3, f={}, z=3, x=?]
[x=1, x=2, x=3, f={}, z=3, x=?]
[x=0, x=1, x=2, x=3, f{}, z=3, x=?]
[x=0, x=1, x=2, x=3, f={}, z=1, x=?]
[res=1 x=0, x=1, x=2, x=3, f={}, z=1,
[x=1, x=2, x=3, f={}, z=2, x=?]
[res=2, x=1, x=2, x=3, f={}, z=2, x=?]
[x=2, x=3, f={}, z=4, x=?]
[res-4, x-2, x=3, f={}, z=4, x=?]
[x=3, f={}, z=8, x=?]
[res-8, x-3, f={}, z-8, x=?]
11 [f-{}, z-8, x-8]
12 [z-8, x=8]
13 [1

Consider the following block. Assume static scoping and call-by-value parameter passing.
1 = {
2
WNH
3
L
10
11
12
13
};
int x;
int z;
z :=4;
{
};
int f(int x) {
if x==0 then {
z = 1 }
else {
z = f(x-1) *z+2 };
return z;
};
x := f (3);
Demonstrate the computations that take place during the evaluation of this block, that is, give a
sequence of lines each showing the complete runtime stack with all activation records after each
statement or function call. For recursive calls use one stack onto which a new activation record is
pushed on for each recursive function call.

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