Definition 17.5.2. (Modular Equivalence, second definition) a = b (mod n) iff a-b=k-n, where k is an integer (that is, k € Z). A Exercise 17.5.3. Using Definition 17.5.2, show that equivalence mod n is an equivalence relation. (That is, show that equivalence mod n is (a) reflexive, (b) symmetric, and (c) transitive)

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter1: Fundamentals
Section1.7: Relations
Problem 4E: 4. Let be the relation “congruence modulo 5” defined on as follows: is congruent to modulo if...
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Please do Exercise 17.5.3 and please show step by step and explain

Definition 17.5.2. (Modular Equivalence, second definition)
a = b (mod n) iff a-b=k-n, where k is an integer (that is, k € Z). A
Exercise 17.5.3. Using Definition 17.5.2, show that equivalence mod n
is an equivalence relation. (That is, show that equivalence mod n is (a)
reflexive, (b) symmetric, and (c) transitive)
Transcribed Image Text:Definition 17.5.2. (Modular Equivalence, second definition) a = b (mod n) iff a-b=k-n, where k is an integer (that is, k € Z). A Exercise 17.5.3. Using Definition 17.5.2, show that equivalence mod n is an equivalence relation. (That is, show that equivalence mod n is (a) reflexive, (b) symmetric, and (c) transitive)
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