defined on the set 10 Consider the vector field F(x, y, z) = (= + 2²,5 = +2²) N = {(x, y, z) € R³ : -5 < r < 0,0 < y < 6,0 < z < 1 + x² + y²}. Then (A) curl F ‡ (0, 0, 0) in (2 (B) curl F = (0, 0, 0) in 2, but F is not conservative in 2 since 2 is not simply connected 1 (C) the function defined by (x. y. 2) = log r -+5y, V(r,y,z) €, is a potential of 2 (D) F is conservative in 2
defined on the set 10 Consider the vector field F(x, y, z) = (= + 2²,5 = +2²) N = {(x, y, z) € R³ : -5 < r < 0,0 < y < 6,0 < z < 1 + x² + y²}. Then (A) curl F ‡ (0, 0, 0) in (2 (B) curl F = (0, 0, 0) in 2, but F is not conservative in 2 since 2 is not simply connected 1 (C) the function defined by (x. y. 2) = log r -+5y, V(r,y,z) €, is a potential of 2 (D) F is conservative in 2
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter5: Inner Product Spaces
Section5.CM: Cumulative Review
Problem 5CM: Take this test to review the material in Chapters 4 and 5. After you are finished, check your work...
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![10 Consider the vector field F(x, y, z) = ( = + z², 5, = + 2²)
defined on the set
N = {(x, y, z) € R³ : -5 < a < 0,0 < y < 6,0 < z < 1 + x² + y²}.
Then
(A) curl F ‡ (0, 0, 0) in 2
(B) curl F = (0, 0, 0) in 2, but F is not conservative in 2 since 2 is not simply connected
1
(C) the function 4 defined by (r. y, z) = log r - - + 5y. V(x, y, z) € 9, is a potential of
F in Q
(D) F is conservative in 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdf0a5446-7c8f-4e18-a28a-efa1dda355a7%2Fb50b431b-6f55-431e-b504-5655edfc7155%2Fm96cniff_processed.jpeg&w=3840&q=75)
Transcribed Image Text:10 Consider the vector field F(x, y, z) = ( = + z², 5, = + 2²)
defined on the set
N = {(x, y, z) € R³ : -5 < a < 0,0 < y < 6,0 < z < 1 + x² + y²}.
Then
(A) curl F ‡ (0, 0, 0) in 2
(B) curl F = (0, 0, 0) in 2, but F is not conservative in 2 since 2 is not simply connected
1
(C) the function 4 defined by (r. y, z) = log r - - + 5y. V(x, y, z) € 9, is a potential of
F in Q
(D) F is conservative in 2
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