Define H: R (1) R (1) and J: R (1) R{1} as follows. - H(x)=3(x) = x + 1 x-1 for each x R {1} Compute the compositions H. J and J. H to determine if J and H are inverses for each other. (Simplify your answers completely.) For every x in R - {1}, (H. J)(x)H(J(x)) = H x+1 +1 x-1 2x 1 Now use the definition to find J. H. - For every x in R (1), (J. H)(x) = J Thus, --Select--- ◇ the identity function on R (1), and so H and ---Select--- inverses for each other. -

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.1: Inverse Functions
Problem 19E
Question
Define H: R (1) R (1) and J: R (1) R{1} as follows.
-
H(x)=3(x) =
x + 1
x-1
for each x R {1}
Compute the compositions H. J and J. H to determine if J and H are inverses for each other. (Simplify your answers completely.)
For every x in R - {1},
(H. J)(x)H(J(x)) = H
x+1
+1
x-1
2x
1
Now use the definition to find J. H.
-
For every x in R (1), (J. H)(x) = J
Thus, --Select---
◇ the identity function on R (1), and so H and ---Select--- inverses for each other.
-
Transcribed Image Text:Define H: R (1) R (1) and J: R (1) R{1} as follows. - H(x)=3(x) = x + 1 x-1 for each x R {1} Compute the compositions H. J and J. H to determine if J and H are inverses for each other. (Simplify your answers completely.) For every x in R - {1}, (H. J)(x)H(J(x)) = H x+1 +1 x-1 2x 1 Now use the definition to find J. H. - For every x in R (1), (J. H)(x) = J Thus, --Select--- ◇ the identity function on R (1), and so H and ---Select--- inverses for each other. -
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