Define f: R→ R and g: RR by the formulas f(x) = x + 7 and g(x) = -x for each x E R. Find the following. (gof) f-1 og ¹ 11 || || 1 State how (g of)-1 and f-1 o g-¹ are related. -1 1 O (gof)-¹ is always greater than f-¹ og ¹. O (gof)-¹ and f-1 o g¹ are not related. -1 O (gof)¹ and f-¹ o g¹ are always equal. -1 O (gof)-¹ and f-1 o g¹ are sometimes not equal. 1 -1 O (gof)-¹ is always less than f-¹ og ¹,
Define f: R→ R and g: RR by the formulas f(x) = x + 7 and g(x) = -x for each x E R. Find the following. (gof) f-1 og ¹ 11 || || 1 State how (g of)-1 and f-1 o g-¹ are related. -1 1 O (gof)-¹ is always greater than f-¹ og ¹. O (gof)-¹ and f-1 o g¹ are not related. -1 O (gof)¹ and f-¹ o g¹ are always equal. -1 O (gof)-¹ and f-1 o g¹ are sometimes not equal. 1 -1 O (gof)-¹ is always less than f-¹ og ¹,
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 36E
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![Define f: R → R and g: R→IR by the formulas f(x) = x + 7 and g(x) = -x for each x E R.
Find the following.
(gof)-¹
9-1
f-1 =
f-1 og ¹ =
State how (gof)-1 and f-1 o g-1 are related.
O (gof)-¹ is always greater than f-¹ og¯¹.
O (gof)-¹ and f-1 o g¹ are not related.
1
O (gof)-¹ and f-1 o g¹ are always equal.
O (gof)-¹ and f-1 o g¹ are sometimes not equal.
O (gof)-¹ is always less than f-1 o g-¹,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa0e38307-1ade-44bc-b712-aaeda4c58098%2Ff9c2aae8-8788-4eea-85f0-7bc75bfcb6cd%2Fwz39djs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Define f: R → R and g: R→IR by the formulas f(x) = x + 7 and g(x) = -x for each x E R.
Find the following.
(gof)-¹
9-1
f-1 =
f-1 og ¹ =
State how (gof)-1 and f-1 o g-1 are related.
O (gof)-¹ is always greater than f-¹ og¯¹.
O (gof)-¹ and f-1 o g¹ are not related.
1
O (gof)-¹ and f-1 o g¹ are always equal.
O (gof)-¹ and f-1 o g¹ are sometimes not equal.
O (gof)-¹ is always less than f-1 o g-¹,
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