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Defective alternator and corroded or loose battery charges are a few of the main causes of battery degradation. A company producing automobile batteries is developing a prototype on their next product and that they claim their batteries will last on average, 3 years with a variance of 1 year. A random sample of 5 prototype batteries were taken and in the course of the company's product development, have measured their lifetimes as 1.9, 2.4, 3.0, 3.5, and 4.2 years. s?=0.81s Construct a 95% confidence interval for o and decide if the company's claim that o² = 1 is valid. Assume the population of battery lives to be approximately normally distributed. Oa029

Defective alternator and corroded or loose battery charges are a few of the main causes of battery degradation. A company producing automobile batteries is developing a prototype on their next product and that they claim their batteries will last on average, 3 years with a variance of 1 year. A random sample of 5 prototype batteries were taken and in the course of the company's product development, have measured their lifetimes as 1.9, 2.4, 3.0, 3.5, and 4.2 years. s?=0.81s Construct a 95% confidence interval for o and decide if the company's claim that o² = 1 is valid. Assume the population of battery lives to be approximately normally distributed. Oa029

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Cl on Variance Defective alternator and corroded or loose battery charges are a few of the main causes of battery degradation. A company producing automobile batteries is developing a prototype on their next product and that they claim their batteries will last on average, 3 years with a variance of 1 year. A random sample of 5 prototype batteries were taken and in the course of the company's product development, have measured their lifetimes as 1.9, 2.4, 3.0, 3.5, and 4.2 years. s2 = 0.815 Construct a 95% confidence interval for o² and decide if the company's claim that o2 =1 is valid. Assume the population of battery lives to be approximately normally distributed. O a. 0.29 < o? < 6,74. Because 95% confidence interval for o? is (0.29, 6.74), and the 1 is in that interval, we can conclude that the company's claim that o² = 1 is valid O b.0.539 < o? <2.596. Because 95% confidence interval for o? is (0.539, 2.596), and the 1 is in that interval, we can conclude that the company's claim that o2 = 1 is valid OC.0.34 <g? <4.59. Because 95% confidence interval for o? is (0.34, 4.59), and the s?= 0.815 is in that interval, we can conclude that the company's claim is valid O d. 0.29 <o <6.74. Because 95% confidence interval for o is (0.29, 6.74), and the s = 0.815 is in that interval, we can conclude that the company's claim is valid
Transcribed Image Text:Cl on Variance Defective alternator and corroded or loose battery charges are a few of the main causes of battery degradation. A company producing automobile batteries is developing a prototype on their next product and that they claim their batteries will last on average, 3 years with a variance of 1 year. A random sample of 5 prototype batteries were taken and in the course of the company's product development, have measured their lifetimes as 1.9, 2.4, 3.0, 3.5, and 4.2 years. s2 = 0.815 Construct a 95% confidence interval for o² and decide if the company's claim that o2 =1 is valid. Assume the population of battery lives to be approximately normally distributed. O a. 0.29 < o? < 6,74. Because 95% confidence interval for o? is (0.29, 6.74), and the 1 is in that interval, we can conclude that the company's claim that o² = 1 is valid O b.0.539 < o? <2.596. Because 95% confidence interval for o? is (0.539, 2.596), and the 1 is in that interval, we can conclude that the company's claim that o2 = 1 is valid OC.0.34 <g? <4.59. Because 95% confidence interval for o? is (0.34, 4.59), and the s?= 0.815 is in that interval, we can conclude that the company's claim is valid O d. 0.29 <o <6.74. Because 95% confidence interval for o is (0.29, 6.74), and the s = 0.815 is in that interval, we can conclude that the company's claim is valid
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