def substring with largest sum(string: str) -> str: wwwwin Given a string , return the substring with the largest sum (as calculated by sum_string()) that exists within . If there are multiple substrings with equally large sums, return the first one that occurs. The substring could just be the whole string itself, or it could be empty. To calculate the sum of the substring, please use the function sum_string() which you have implemented above as a helper. For example, given the string "321", there are 7 possible substrings: "3", "2", "1", "32", "21", "321". For each one of them, their sum can be calculated as per the sum string() function which you have already implemented. By using your understanding of loops, implement this function to return the substring with the largest sum by checking all of the substrings of the input string. So, "32" evaluates to 1, "21" also evaluates to 1, "321" evaluates to 2, resulting in "3" being the largest possible substring as it evaluates to 3.

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Do not add any imports. You may not use any lists or list methods or any while loops. You must not use any break or continue statements. Please do not use try-except statements
# Function to perform the sum of string elements as per the condition
2 def sum string(input_string) -> int:
1
3.
result = 0
4.
i=0
for element in input_string:
converted_num = int (element)
e):
result
5-
6.
if(i%2
result + converted_num
%3D
9-
else:
result
result - converted_num
10
%3D
11
i-i+1
12
return result
13
14
15 print("For string 54321 result is : ",end=" ")
16 print(sum_string("54321"))
17 print("For empty string result is : ", end=" ")
18 print(sum string(""))
Transcribed Image Text:# Function to perform the sum of string elements as per the condition 2 def sum string(input_string) -> int: 1 3. result = 0 4. i=0 for element in input_string: converted_num = int (element) e): result 5- 6. if(i%2 result + converted_num %3D 9- else: result result - converted_num 10 %3D 11 i-i+1 12 return result 13 14 15 print("For string 54321 result is : ",end=" ") 16 print(sum_string("54321")) 17 print("For empty string result is : ", end=" ") 18 print(sum string(""))
def substring with largest sum(string: str) -> str:
Given a string <string>, return the substring with the largest sum (as
calculated by sum_string()) that exists within <string>. If there are
multiple substrings with equally large sums, return the first one that
occurs. The substring could just be the whole string itself, or it could
be empty.
To calculate the sum of the substring, please use the function sum_string()
which you have implemented above as a helper.
For example, given the string "321", there are 7 possible substrings:
", "3", "2", "1", "32", "21", "321". For each one of them, their sum can
be calculated as per the sum string0 function which you have already
implemented. By using your understanding of loops, implement this function
to return the substring with the largest sum by checking all of the
substrings of the input string, So, "32" evaluates to 1, "21" also
evaluates to 1, "321" evaluates to 2, resulting in "3" being the largest
possible substring as it evaluates to 3.
Transcribed Image Text:def substring with largest sum(string: str) -> str: Given a string <string>, return the substring with the largest sum (as calculated by sum_string()) that exists within <string>. If there are multiple substrings with equally large sums, return the first one that occurs. The substring could just be the whole string itself, or it could be empty. To calculate the sum of the substring, please use the function sum_string() which you have implemented above as a helper. For example, given the string "321", there are 7 possible substrings: ", "3", "2", "1", "32", "21", "321". For each one of them, their sum can be calculated as per the sum string0 function which you have already implemented. By using your understanding of loops, implement this function to return the substring with the largest sum by checking all of the substrings of the input string, So, "32" evaluates to 1, "21" also evaluates to 1, "321" evaluates to 2, resulting in "3" being the largest possible substring as it evaluates to 3.
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