def find_positive_value_coordinates(lst: list[list[int]]) -> list[list[int]]: "" Takes in a nested list of integers and returns a nested list of integers such that each element in the returned list represents coordinates where a positive value is in . >>> lst = [[6, -4, 01, [-2, -10, 8, -71], [99, 43], [], [-5]] >>> find_positive_value_coordinates(lst) [[0, 0], [1, 2], [2, 0], [2, 1]] >>> lst = [[1, 2], [3, 4]] >>> find_positive_value_coordinates(lst) [[0, 0], [0, 1], [1, 0], [1, 1]] >>> lst = [[-1, -2], [-3, -4]] >>> find_positive_value_coordinates(lst) [] coordinates = [] for i in [BLANK_1]: for j in [BLANK_2]: if [BLANK_3]: coordinates. [BLANK_4] return coordinates Please note: BLANK 1 through BLANK 4 are just placeholders that you are required to fill in using the drop-down options presented to you.

def find_positive_value_coordinates(lst: list[list[int]]) -> list[list[int]]: "" Takes in a nested list of integers and returns a nested list of integers such that each element in the returned list represents coordinates where a positive value is in . >>> lst = [[6, -4, 01, [-2, -10, 8, -71], [99, 43], [], [-5]] >>> find_positive_value_coordinates(lst) [[0, 0], [1, 2], [2, 0], [2, 1]] >>> lst = [[1, 2], [3, 4]] >>> find_positive_value_coordinates(lst) [[0, 0], [0, 1], [1, 0], [1, 1]] >>> lst = [[-1, -2], [-3, -4]] >>> find_positive_value_coordinates(lst) [] coordinates = [] for i in [BLANK_1]: for j in [BLANK_2]: if [BLANK_3]: coordinates. [BLANK_4] return coordinates Please note: BLANK 1 through BLANK 4 are just placeholders that you are required to fill in using the drop-down options presented to you.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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let buckets (f:'a->'a->bool) (lst:'a list): 'a list list = let rec find (find_f: 'a->'a->bool)(find_ht: 'a) (find_acc:'a list list):'a list list = match find_acc with []-> [[find_ht]] | head::tail -> match head with h::_-> if f h find_ht then (find_ht::head)::tail else head::(find f find_ht tail) in let rec parse (parse_f: 'a->'a->bool) (parse_lst:'a list) (parse_acc: 'a list list): 'a list list = match parse_lst with [] -> parse_acc | ht::tl -> parse f tl (find f ht parse_acc) in match lst with []->[] | ht::tl -> parse f tl [[ht]];; let buckets (f:'a->'a->bool) (lst:'a list): 'a list list = let rec find (find_f: 'a->'a->bool)(find_ht: 'a) (find_acc:'a list list):'a list list = match find_acc with []-> [[find_ht]] | head::tail -> match head with h::_-> if f h find_ht then (find_ht::head)::tail else head::(find f find_ht tail) in let rec parse (parse_f: 'a->'a->bool)…
Here is the code for number 1. def reverse_list(old_list): new_list = [ele for ele in reversed(old_list)] return new_list if __name__ == "__main__": str = input("Enter the elements of the list: ").split() elements = list(map(int, str)) print(reverse_list(elements))
Project 2: Singly-Linked List The purpose of this assignment is to assess your ability to: ▪Implement sequential search algorithms for linked list structures ▪Implement sequential abstract data types using linked data ▪Analyze and compare algorithms for efficiency using Big-O notation For this assignment, you will implement a singly-linked node class. Use your singly-linked node to implement a singly-linked list class that maintains its elements in ascending order. The SinglyLinkedList class is defined by the following data: ▪A node pointer to the front and the tail of the list Implement the following methods in your class: ▪A default constructor list<T> myList ▪A copy constructor list<T> myList(aList) ▪Access to first elementmyList.front() ▪Access to last elementmyList.back() ▪Insert value myList.insert(val) ▪Remove value at frontmyList.pop_front() ▪Remove value at tailmyList.pop_back() ▪Determine if emptymyList.empty() ▪Return # of elementsmyList.size() ▪Reverse order of…
def my_index_1(my_list:List[int], my_element:int)->int:"""Our version of the one-argument version of the index function.https://docs.python.org/dev/library/stdtypes.html#common-sequence-operations)This function takes a list and an element, and returns the smallestindex where the element occurs in the list. This function returnsNone if the element is not in the list.Arguments:my_list (list): A list of integers.my_element (int): The element to be found.Returns:int: The smallest index at which my_element is found in my_list.Examples:>>> print(my_index_1([], 2))None>>> print(my_index_1([1, 2, 3], 2))1>>> print(my_index_1([3, 1, 2, 3, 1], 2))2>>> print(my_index_1([3, 1, 2, 3, 1], 3))0""" Please solve this in Python
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def grade_manipulation(grade_list): ''' Question You are working as a TA and the professor asks you to handle the uncleaned student grades. - First, substitute all grades that are None with a 0 - Second, reverse the order of the student grades - Third, change the type of the list to a tuple Args: grade_list (list) Returns: tuple >>> grade_manipulation([67, 95, 60, None, 100]) (100, 0, 60, 95, 67) ''" # print(grade_manipulation([67, 95, 60, None, 100])) # print('---')
With Head node or not? statement is: if(p->rlink != first) p = p->rlink; O a. It is a Doubly linked list without Head node. O b. It is a Doubly linked list with Head node.