def combi(gut): if len(gut) < 1: return [""] [] tin for isa in range(len(gut)): for jas in combi(gut[:isa] + gut[isa+1:]): tin.append (gut[isa] + jas) return tin If gut has length n, what is the recurrence relation of the running time of combi(gut)? Assume that appending to a list and string concatenation both run in constant time. (Hint: Determine the number of elements combi(gut) returns first.) T(n) =

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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I am very eager to learn. Please explain briefly. You may provide equations as well.

def combi(gut):
if len(gut) < 1:
return [""]
tin = []
for isa in range(len(gut)):
for jas in combi(gut[:isa] + gut[isa+1:]):
tin.append (gut[isa] + jas)
return tin
If gut has length n, what is the recurrence relation of the running time of combi(gut)?
Assume that appending to a list and string concatenation both run in constant time.
(Hint: Determine the number of elements combi(gut) returns first.)
T(n) =
%3D
Transcribed Image Text:def combi(gut): if len(gut) < 1: return [""] tin = [] for isa in range(len(gut)): for jas in combi(gut[:isa] + gut[isa+1:]): tin.append (gut[isa] + jas) return tin If gut has length n, what is the recurrence relation of the running time of combi(gut)? Assume that appending to a list and string concatenation both run in constant time. (Hint: Determine the number of elements combi(gut) returns first.) T(n) = %3D
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